4*3*2*1 = 24 ways.
There are n! (n factorial) ways that n people can stand in line. So six people can stand in line in: 1*2*3*4*5*6 = 720 different ways
I make it 136 ways.
If the people are always facing forward? 24 ways.
There are 19 ways to do this.
for the first student in the line there are 10 choices, then for the second 9 choices left, for the third 8 choices left and so on... So it's 10x9x8x7x6x5x4x3x2x1 = 3628800
128
There are 5040 ways.
5040
There are n! (n factorial) ways that n people can stand in line. So six people can stand in line in: 1*2*3*4*5*6 = 720 different ways
36
5! (5 factorial), which is 1 x 2 x 3 x 4 x 5.
7
The number of ways to arrange six students in a lunch line can be calculated using the factorial of the number of students. Specifically, this is 6! (6 factorial), which equals 6 × 5 × 4 × 3 × 2 × 1 = 720. Therefore, there are 720 different ways to arrange six students in a lunch line.
I make it 136 ways.
If the people are always facing forward? 24 ways.
20*19*18*17*16 = 1860480 ways.
Not sure what a strait line is! Five people can stand in a straight line, with Jessie third in 24 ways if you ignore left-to-right and right-to-left "reflections".