If the order is important, then: 9 choices for the first chair, 8 choices for the second, and 7 choices for the third = 9 x 8 x 7 = 504 ways. If order doesn't matter, then once you've picked 3 people, there are 6 ways to arrange them in the chairs, so divide by 6, or 84 ways.
See related link on combinations and permutations for more information on these types of problems.
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6 people multiplied by 6 different chairs meaning there are a total of 36 different combinations because each chair has 6 different combinations. - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Rafaelrz. If you have 6 chairs in a row, and 6 persons are going to be seated in those chairs, the number of different arrangements (permutations) the 6 people can be seated is 6! (six factorial): 6! = 6x5x4x3x2x1 = 720 i.e., The first person to sit has 6 options. For each option of the first person the second has 5 options. For each option of the second person the third has 4 options. And so on.
3*2*1 = 6 ways.
6 tables will be left out without atleast 1 person...
720