There are 8!/(4!*4!) = 70 ways.
-5
3 people can be selected from a pool of 7 people in (7 x 6 x 5) = 210 ways.But each group of 3 can be selected and seated in (3 x 2 x 1) = 6 ways.So the number of different 3-person subcommittees formed from 7 people is (210/6) = 35 .
-6
24 - 1
If the events can be considered independent then the probability is (0.7)4 = 0.24 approx.
-5
-4
3 people can be selected from a pool of 7 people in (7 x 6 x 5) = 210 ways.But each group of 3 can be selected and seated in (3 x 2 x 1) = 6 ways.So the number of different 3-person subcommittees formed from 7 people is (210/6) = 35 .
Believe it or not you can do this in your head: It's easier to think of the number of ways to exclude 2 potential subcommittee members. Say you exclude #1. Then there are 5 ways to exclude a second. If you exclude #2, there are only 4 unique ways to exclude a second (since excluding 2 and 1 is the same as excluding 1 and 2) Exclude #3 and there are 3 ways… answer 5+4+3+2+1=15 ways
-1
-6
Nine people can be selected from the group in(12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4) = 79,833,600ways.But each group of the same 9 people can be selected in(9 x 8 x 7 x 6 x 5 x 4 x 3 x 2) = 362,880 different orders.So the number of different 9-person committees that can be selected is79,833,600/362,880 = 220 .
4 people can be selected from a pool of 15 people in (15 x 14 x 13 x 12) = 32,760 ways.But each group of 4 can be selected and seated in (4 x 3 x 2 x 1) = 24 ways.So the number of different 4-person subcommittees formed from 15 people is (32,760 / 4) = 8,190 .
The short notation of this would be 12C2 There are 12 possible selections for the first person, and 11 possible selections for the second person. 12x11 is 132 But half of these options are the same as another option but with the people being picked the other way around, so for the real value we need to do 132/2 or 66. Thus, there are 66 ways a committee of 2 can be selected from a club with 12 members.
Private means for use by one person or by selected people. Non-public.
Nine people can be selected from the group of 12 in(12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4) = 79,833,600ways.But each group of the same 9 people can be selected in(9 x 8 x 7 x 6 x 5 x 4 x 3 x 2) = 362,880 different orders.So the number of different 9-person committees that can be selected is79,833,600/362,880 = 220 .
A 9 person jury, final 3