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How many ways can a committee of 3 students be chosen from a total count of 1514 students?
The first member chosen can be any one of 1,514 students.
The second member chosen can be any one of the remaining 1,513 students.
The third member chosen can be any one of the remaining 1,512 students.
So there are (1,514 x 1,513 x 1,512) ways to choose three students.
But for every group of three, there are (3 x 2 x 1) = 6 different orders in which the same 3 can be chosen.
So the number of `distinct, unique committees of 3 students is
(1514 x 1513 x 1512) / 6 = 577,251,864
What else can I help you with?
How many ways can a committee of three be chosen from a total amount of 4463 students?
The first member chosen can be any one of 4,463 students.The second member chosen can be any one of the remaining 4,462 students.The third member chosen can be any one of the remaining 4,461 students.So there are (4,463 x 4,462 x 4,461) ways to choose three students.But for every group of three, there are (3 x 2 x 1) = 6 different orders in which the same 3 can be chosen.So the number of `distinct, unique committees of 3 students is(4463 x 4462 x 4461) / 6 = 14,805,989,111
In a second grade class containing 13 girls and 9 boys 2 students are selected at random to give out the math papers. What is the probability that the second student chosen is a boy given that the fir?
To find the probability that the second student chosen is a boy given that the first student chosen is a boy, we first note that there are 22 students total (13 girls and 9 boys). If the first student chosen is a boy, there will then be 8 boys and 13 girls remaining, making a total of 21 students left. Therefore, the probability that the second student is a boy is the number of remaining boys (8) divided by the total remaining students (21), which gives us a probability of ( \frac{8}{21} ).
A nursing class has 13 women and 18 men If a student is chosen randomly to be the team leader what is the probability the student is a woman?
The probability that a randomly chosen student is a woman can be calculated by dividing the number of women by the total number of students in the class. In this case, there are 13 women and 31 total students, so the probability is 13/31, which simplifies to approximately 0.419 or 41.9%.
4 students in a class of 12. How many ways can the students be chosen if they are each given a different task?
To determine how many ways 4 students can be chosen from a class of 12 and assigned different tasks, we first select 4 students from the 12, which can be done in ( \binom{12}{4} ) ways. Then, we can assign the 4 different tasks to these students in ( 4! ) (24) ways. Therefore, the total number of ways to choose the students and assign the tasks is ( \binom{12}{4} \times 4! = 495 \times 24 = 11,880 ).
Ther are 9 girls and 12 boys on the student councilwhat is the probabilitythat a girl will be chosen as president?
To find the probability that a girl will be chosen as president, you can use the formula for probability: ( P(\text{girl}) = \frac{\text{number of girls}}{\text{total number of students}} ). There are 9 girls and 12 boys, making a total of 21 students. Thus, the probability is ( P(\text{girl}) = \frac{9}{21} = \frac{3}{7} ).
How many different committees can be formed from 11 teachers and 48 students?
To determine the number of different committees that can be formed from 11 teachers and 48 students, we need to clarify the size of the committee and whether there are any restrictions on the selection. If we assume that any combination of teachers and students can be chosen without restrictions, the total number of possible combinations is (2^{11} \cdot 2^{48} = 2^{59}). This accounts for every possible subset of teachers and students, including the empty committee.
What is the probability a girl is chosen if 15 students are girls and 10 students are boys?
The ratio of girls to total students is 15:25, or 3:5. Three out of five students are girls so there would be a 60% probability that a girl would be chosen; a 2 out of 5 chance, or 40% probability that a boy would be chosen.
A school committee consists of 2 teachers and 4 students. The number of different committees that can be formed from 5 teachers and 10 students is?
To form a committee of 2 teachers from 5, we use the combination formula ( \binom{n}{r} ), where ( n ) is the total number and ( r ) is the number chosen. The number of ways to choose 2 teachers from 5 is ( \binom{5}{2} = 10 ). For the 4 students from 10, the number of ways is ( \binom{10}{4} = 210 ). Therefore, the total number of different committees is ( 10 \times 210 = 2100 ).
How many ways can a committee of 6 be chosen from 5 teachers and 4 students if all are equally eligible?
There are 84 different combinations possible for the committee of 6, taken from4 students and 5 teachers.1.- The committee with 4 students has 4C4 number of combinations of 4 students out of 4 and 5C2 number of combinations of 2 teachers out of 5 to be combined with. The product of these two give the number of different combinations possible in a committee formed by 4 students and 2 teachers.2.- The committee with 3 students has 4C3 number of combinations of 3 students out of 4 and 5C3 number of combinations of 3 teachers out of 5 to be combined with. The product of these two give the number of different combinations possible in a committee formed by 3 students and 6 teachers.3.- The committee with 2 students has 4C2 number of combinations of 2 studentsout of 4 and 5C4 number of combinations of 4 teachers out of 5 to be combined with. The product of these two give the number of different combinations possible in a committee formed by 2 students and 4 teachers.4.- The committee with 1 student has 4C1 number of combinations of 1 student out of 4 students and 5C5 number of combinations of 5 teachers out of 5 to be combined with. The product of these two give the number of different combinations possible in a committee formed by 1 student and 5 teachers.We now add up all possible combinations:4C4∙5C2 + 4C3∙5C3 + 4C2∙5C4 + 4C1∙5C5 = 1(10) + 4(10) +6(5) + 4(1) = 84There are 84 different combinations possible for the committee of 6, taken from4 students and 5 teachers.[ nCr = n!/(r!(n-r)!) ][ n! = n(n-1)(n-2)∙∙∙(3)(2)(1) ]
A committee consists of 7 women and 4 men if a member of the committee is chosen at random to act as a chairman what is the probability that the choice is a woman?
There are 11 people total and 7 women. The probability the chairman is a woman is 7/11.
How many ways can a committee of three be chosen from a total amount of 4463 students?
The first member chosen can be any one of 4,463 students.The second member chosen can be any one of the remaining 4,462 students.The third member chosen can be any one of the remaining 4,461 students.So there are (4,463 x 4,462 x 4,461) ways to choose three students.But for every group of three, there are (3 x 2 x 1) = 6 different orders in which the same 3 can be chosen.So the number of `distinct, unique committees of 3 students is(4463 x 4462 x 4461) / 6 = 14,805,989,111
In a second grade class containing 13 girls and 9 boys 2 students are selected at random to give out the math papers. What is the probability that the second student chosen is a boy given that the fir?
To find the probability that the second student chosen is a boy given that the first student chosen is a boy, we first note that there are 22 students total (13 girls and 9 boys). If the first student chosen is a boy, there will then be 8 boys and 13 girls remaining, making a total of 21 students left. Therefore, the probability that the second student is a boy is the number of remaining boys (8) divided by the total remaining students (21), which gives us a probability of ( \frac{8}{21} ).
Does the work cited count towards the total word count?
No, the work cited does not count towards the total word count.
How do you get a total from a group of averages?
Average = Total/Count so Total = Average*Count.
A nursing class has 13 women and 18 men If a student is chosen randomly to be the team leader what is the probability the student is a woman?
The probability that a randomly chosen student is a woman can be calculated by dividing the number of women by the total number of students in the class. In this case, there are 13 women and 31 total students, so the probability is 13/31, which simplifies to approximately 0.419 or 41.9%.
4 students in a class of 12. How many ways can the students be chosen if they are each given a different task?
To determine how many ways 4 students can be chosen from a class of 12 and assigned different tasks, we first select 4 students from the 12, which can be done in ( \binom{12}{4} ) ways. Then, we can assign the 4 different tasks to these students in ( 4! ) (24) ways. Therefore, the total number of ways to choose the students and assign the tasks is ( \binom{12}{4} \times 4! = 495 \times 24 = 11,880 ).
Does the works cited count towards the total word count of a document?
No, the works cited page typically does not count towards the total word count of a document.
