The first member chosen can be any one of 1,514 students.
The second member chosen can be any one of the remaining 1,513 students.
The third member chosen can be any one of the remaining 1,512 students.
So there are (1,514 x 1,513 x 1,512) ways to choose three students.
But for every group of three, there are (3 x 2 x 1) = 6 different orders in which the same 3 can be chosen.
So the number of `distinct, unique committees of 3 students is
(1514 x 1513 x 1512) / 6 = 577,251,864
The first member chosen can be any one of 4,463 students.The second member chosen can be any one of the remaining 4,462 students.The third member chosen can be any one of the remaining 4,461 students.So there are (4,463 x 4,462 x 4,461) ways to choose three students.But for every group of three, there are (3 x 2 x 1) = 6 different orders in which the same 3 can be chosen.So the number of `distinct, unique committees of 3 students is(4463 x 4462 x 4461) / 6 = 14,805,989,111
The probability that a randomly chosen student is a woman can be calculated by dividing the number of women by the total number of students in the class. In this case, there are 13 women and 31 total students, so the probability is 13/31, which simplifies to approximately 0.419 or 41.9%.
This is the total count of colonia which can grout without oxigen
To determine how many students practiced the piano for more than 3 hours a week, you would need to analyze the data presented in the plot graph. Look for the section of the graph that represents practice times exceeding 3 hours and count the number of students indicated in that range. The total from that segment will give you the answer. If you have the graph, you can visually identify and count those students directly.
“What is the student enrollment (in the total number of students)?”
The ratio of girls to total students is 15:25, or 3:5. Three out of five students are girls so there would be a 60% probability that a girl would be chosen; a 2 out of 5 chance, or 40% probability that a boy would be chosen.
There are 11 people total and 7 women. The probability the chairman is a woman is 7/11.
To calculate the number of ways a committee of 6 can be chosen from 5 teachers and 4 students, we use the combination formula. The total number of ways is given by 9 choose 6 (9C6), which is calculated as 9! / (6! * 3!) = 84. Therefore, there are 84 ways to form a committee of 6 from 5 teachers and 4 students if all are equally eligible.
The first member chosen can be any one of 4,463 students.The second member chosen can be any one of the remaining 4,462 students.The third member chosen can be any one of the remaining 4,461 students.So there are (4,463 x 4,462 x 4,461) ways to choose three students.But for every group of three, there are (3 x 2 x 1) = 6 different orders in which the same 3 can be chosen.So the number of `distinct, unique committees of 3 students is(4463 x 4462 x 4461) / 6 = 14,805,989,111
No, the work cited does not count towards the total word count.
Average = Total/Count so Total = Average*Count.
The probability that a randomly chosen student is a woman can be calculated by dividing the number of women by the total number of students in the class. In this case, there are 13 women and 31 total students, so the probability is 13/31, which simplifies to approximately 0.419 or 41.9%.
No, the works cited page typically does not count towards the total word count of a document.
This is the total count of colonia which can grout without oxigen
To determine how many students practiced the piano for more than 3 hours a week, you would need to analyze the data presented in the plot graph. Look for the section of the graph that represents practice times exceeding 3 hours and count the number of students indicated in that range. The total from that segment will give you the answer. If you have the graph, you can visually identify and count those students directly.
“What is the student enrollment (in the total number of students)?”
Yes, a run scored in baseball does count as a total base.