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Q: In a second grade class containing 13 girls and 9 boys 2 students are selected at random to give out the math papers. What is the probability that the second student chosen is a boy given that the fir?

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There is only one girl out of 12 students so the probability that the girl is selected is 1/12.

Probability of picking a student is 800 / (800+50+150) = 800 / 1000 = .8.

1.6

The probability that a randomly chosen student is a woman can be calculated by dividing the number of women by the total number of students in the class. In this case, there are 13 women and 31 total students, so the probability is 13/31, which simplifies to approximately 0.419 or 41.9%.

The probability is indeterminate. I might ask a student or I might not.

Related questions

The probability is 10 percent.

There is only one girl out of 12 students so the probability that the girl is selected is 1/12.

4 in 7 chance

1/12 =0.08333... ≈ 8.3%

I think it depends on how many students are thinking of alphabet letters at the same time :) The first student will think of a letter from the English alphabet. Then, the second student will think of a letter. The probability that the second student will select what the first student selected is 1/26.

85/500 = 17%

The probability is the number of girls divided by the number of students, so 12/22, or 6/11

110

If there are 12 boys and 6 girls, the total number of students would be 18. You are looking for the probability of selecting a girl from the class: 6/18 Just reduce the fraction to its lowest form 6/18 = 2/6 = 1/3 Your answer would be 1/3.

3 students.

50% of 12 male students = 6 25% of 4 female students = 1 So in total 7 students go for pizza. The probability that a randomly selected student will be female is 1/7 or 14%.

Probability of picking a student is 800 / (800+50+150) = 800 / 1000 = .8.