answersLogoWhite

0

The number of permutations of the letters in PREALGEBRA is the same as the number of permutations of 10 things taken 10 at a time, which is 3,628,800. However, since the letters R, E, and A, are repeated, R=2, E=2, A=2, you must divide that by 2, and 2, and 2 (for a product of 8) to determine the number of distinctpermutations, which is 453,600.

User Avatar

Wiki User

13y ago

Still curious? Ask our experts.

Chat with our AI personalities

TaigaTaiga
Every great hero faces trials, and you—yes, YOU—are no exception!
Chat with Taiga
DevinDevin
I've poured enough drinks to know that people don't always want advice—they just want to talk.
Chat with Devin
ReneRene
Change my mind. I dare you.
Chat with Rene

Add your answer:

Earn +20 pts
Q: How many ways can the letters in prealgebra can arranged?
Write your answer...
Submit
Still have questions?
magnify glass
imp