There are 48 possibilities where 2 of 5 items must be adjacent.
If you have 5 items, and they can be arranged in any order, there are 120
5 x 4 x 3 x 2 ways to arrange them, for example ABCDE, ABCED, and so forth.
However, if any two need to be placed next to each other, the number of variations is reduced to [4 x 3 x 2] x2 (=48), where there are only 4 separate "units" arranged, but the double-unit can appear with either of the pair first.
For example, if A and B must be together, you have 24 possibilities:
(AB)CDE
(AB)CED
(AB)DCE
(AB)DEC
(AB)EDC
(AB)ECD
C(AB)DE
C(AB)ED
D(AB)CE
D(AB)EC
E(AB)CD
E(AB)DC
CD(AB)E
DC(AB)E
CE(AB)D
EC(AB)D
DE(AB)C
ED(AB)C
CDE(AB)
CED(AB)
DEC(AB)
DCE(AB)
EDC(AB)
ECD(AB)
and another 24 where (AB) is replaced by (BA).
5
3 items (or people) can line up in 6 different sequences. 6 items (or people) can line up in 720 different sequences.
To arrange 3 distinct items, you can use the factorial of the number of items, which is calculated as 3! (3 factorial). This equals 3 × 2 × 1 = 6. Therefore, there are 6 different ways to arrange 3 distinct things.
15C3 = 455
Three items can be arranged in (3!) (3 factorial) ways, which is calculated as (3 \times 2 \times 1 = 6). Therefore, there are 6 different ways to arrange 3 items. These arrangements can be represented as permutations of the items.
35,280
5
3 items (or people) can line up in 6 different sequences. 6 items (or people) can line up in 720 different sequences.
To arrange 3 distinct items, you can use the factorial of the number of items, which is calculated as 3! (3 factorial). This equals 3 × 2 × 1 = 6. Therefore, there are 6 different ways to arrange 3 distinct things.
The number of different ways that you can arrange 15 different items is given by the permutations of 15 things taken 15 at a time. That is 15 factorial, or 1,307,674,368,000.
15C3 = 455
7362 7363
you are arranging 70 plants in a rectangular garden with the same number in each row how many ways can you arrange the garden
Three items can be arranged in (3!) (3 factorial) ways, which is calculated as (3 \times 2 \times 1 = 6). Therefore, there are 6 different ways to arrange 3 items. These arrangements can be represented as permutations of the items.
It is elementary division.
If you keep them in a line, there are 24 ways to line them up. Then of course there are squares, diamonds, rectangles, parallelograms, stacks, etc.
1500 billion items are added daily