6 to the power of 6 so 6x6x6x6x6x6=46,656
6
6! = 720
If you have three DIFFERENT letters, you can arrange them in 3! = 1 x 2 x 3 = 6 different ways.
3 items (or people) can line up in 6 different sequences. 6 items (or people) can line up in 720 different sequences.
In a line in 6! = 6*5*4*3*2*1 = 720 ways.
6 -- abc, acb, bac, bca, cab, cba
6
6 to the power of 6 so 6x6x6x6x6x6=46,656
The answer is 5 factorial or 5*4*3*2*1 or 120
6
6! = 720
3*2*1 = 6 ways.
30 ways.
If you have three DIFFERENT letters, you can arrange them in 3! = 1 x 2 x 3 = 6 different ways.
The word "onomatopoeia" has 11 letters, with 6 vowels and 5 consonants. Therefore, there are 11!/(6!5!) = 33,120 ways to arrange the word "onomatopoeia".
This is a Permutation problem; nPr is the formula which assumes order matters. You have n=6 & r=3. Formula is: 6! / (6-3)! or 6!/3! = 120.