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A musician plans to perform 5 selections for a concert if he can choose from 9 different selections how many ways can he arrange his program?

9*8*7*6*5=15,120 ways There are 9 selections to choose from for the first song, 8 for the second, 7 for the third, 6 for the fourth, and 5 for the fifth.


How many ways can you choose 5 from 12?

(12 x 11 x 10 x 9 x 8)/(5 x 4 x 3 x 2) ie 792 ways.


How many ways in which a student can choose 5 out of 9 books if 2 books are compulsory?

Two books are compulsory, so the student really wants to know how many ways he can pick 3 out of 7. That is 35.


How many ways can a group of 12 choose committee of 9?

12C9 = 220


In how many ways can you choose 2 side dishes out of 9?

There are 36 possible combinations.


How many ways can you choose a manager and assistant from a 9-person task force?

72


Given the digits 0-9... how many ways can you form an even number without replacement of numbers?

one digit: 5 ways two digits: 5 * 9 ways three digits: 5 * 9 * 8 ways four digits: 5 * 9 * 8 * 7 ways ... ten digits: 5 * 9! ways So if you have to use ten digits, then the answer is 5 * 9! = 1814400. If you can use anywhere from one to ten digits, then the answer is: 5 * (9! + 8! + 7! + 6! + 5! + 4! + 3! + 2! + 1) = 2045565


How many ways can a construction foreman choose 5 workers for a job if he has a total of 14 workers available?

The number of ways a construction foreman can choose 5 workers from a total of 14 available workers can be calculated using the combination formula ( C(n, r) = \frac{n!}{r!(n-r)!} ). In this case, ( n = 14 ) and ( r = 5 ). Therefore, the calculation is ( C(14, 5) = \frac{14!}{5!(14-5)!} = \frac{14!}{5! \cdot 9!} = 2002 ). Thus, there are 2,002 ways to choose 5 workers.


What could you make 900 with the numbers 1 through 9?

There are many, many ways. Here is one:9*(1+4)*(5+7+8)+6-2*3There are many, many ways. Here is one:9*(1+4)*(5+7+8)+6-2*3There are many, many ways. Here is one:9*(1+4)*(5+7+8)+6-2*3There are many, many ways. Here is one:9*(1+4)*(5+7+8)+6-2*3


How many ways can Justin choose 11 cars from a collection of 20?

Assuming the 20 are all different, there are 20C11 = 20!/(11!*9!) = 167,960 ways.


How many ways can you choose a 3 digit password using 0-9 without repeating the numbers?

10 x 9 x 8 = 720.


HOW many ways can a 9 man baseball batting order be configured?

362880 ways. 9!=9*8*7*6*5*4*3*2*1=362880