(12 x 11 x 10 x 9 x 8)/(5 x 4 x 3 x 2) ie 792 ways.
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You can wind up with 10 different pairs of books in your hand, which you can choose from a shelf of 5 books in 20 different ways.
Since there are 6 numbers that equal 26 to choose from, there are 6 to choose from for the first number, 5 to choose from for the second number, 4 to choose from for the third number, and so on. Therefore there are 6*5*4*3*2*1 ways or 6! or 720.
6*5*4*3 = 360 ways. http://en.wikipedia.org/wiki/Permutations
120 ways.120 ways.120 ways.120 ways.
In combinatorial terms it makes no difference whether you pick one chairperson out of 12 and five other persons, or you pick 6 persons out of 12 and then they pick one of their subgroup to be chair. Number of ways of selecting 1 out of 12 = 12 That leaves 11 persons and you want 5 from them. this can be done in 11C5 = 11*10*9*8*7/(5*4*3*2*1) = 452 ways. So total number of ways = 12*462 = 5544