You can wind up with 10 different pairs of books in your hand, which you can choose from a shelf of 5 books in 20 different ways.
Since there are 6 numbers that equal 26 to choose from, there are 6 to choose from for the first number, 5 to choose from for the second number, 4 to choose from for the third number, and so on. Therefore there are 6*5*4*3*2*1 ways or 6! or 720.
6*5*4*3 = 360 ways. http://en.wikipedia.org/wiki/Permutations
In combinatorial terms it makes no difference whether you pick one chairperson out of 12 and five other persons, or you pick 6 persons out of 12 and then they pick one of their subgroup to be chair. Number of ways of selecting 1 out of 12 = 12 That leaves 11 persons and you want 5 from them. this can be done in 11C5 = 11*10*9*8*7/(5*4*3*2*1) = 452 ways. So total number of ways = 12*462 = 5544
120 ways.120 ways.120 ways.120 ways.
Nine
792 different groups of 5 books, in 95,040 different sequences.
None. If you mean 3 out of 5 then 10
You can wind up with 10 different pairs of books in your hand, which you can choose from a shelf of 5 books in 20 different ways.
There are 4200, in all.
The teacher can choose 5 students out of 12 in 792 different ways using combinations. This calculation is based on the formula for combinations: C(n, k) = n! / [k! * (n - k)!], where n is the total number of students (12) and k is the number of students the teacher wants to choose (5).
There are 12 ways to arrange 5 squares however i want to know what are the ways to do that! Can anybody help me too!!
The answer is 3C2*4C4*5C2 = [3 * 1 * (5*4)/(2*1)] = 3*1*10 = 30 ways.
It would be 5 ways
5 is. (How many different ways are there for him to notchoose one of the five ?)
There are 8 ways to choose the first book There are 7 ways to choose the second book - 8 x 7 = 56 ways to select two books There are 6 ways to choose the third book - 8 x 7 x 6 = 336 way to select three books There are 5 ways to choose the fourth book - 8 x 7 x 6 x 5 = 1,680 ways to select four books.
There is a choice of 5 scarves, and for each scarf a choice of 10 pairs of shoes, giving 5 × 10 = 50 ways.