(12 x 11 x 10 x 9 x 8)/(5 x 4 x 3 x 2) ie 792 ways.
You can wind up with 10 different pairs of books in your hand, which you can choose from a shelf of 5 books in 20 different ways.
Since there are 6 numbers that equal 26 to choose from, there are 6 to choose from for the first number, 5 to choose from for the second number, 4 to choose from for the third number, and so on. Therefore there are 6*5*4*3*2*1 ways or 6! or 720.
6*5*4*3 = 360 ways. http://en.wikipedia.org/wiki/Permutations
120 ways.120 ways.120 ways.120 ways.
In combinatorial terms it makes no difference whether you pick one chairperson out of 12 and five other persons, or you pick 6 persons out of 12 and then they pick one of their subgroup to be chair. Number of ways of selecting 1 out of 12 = 12 That leaves 11 persons and you want 5 from them. this can be done in 11C5 = 11*10*9*8*7/(5*4*3*2*1) = 452 ways. So total number of ways = 12*462 = 5544
Nine
792 different groups of 5 books, in 95,040 different sequences.
None. If you mean 3 out of 5 then 10
You can wind up with 10 different pairs of books in your hand, which you can choose from a shelf of 5 books in 20 different ways.
There are 4200, in all.
12P5 = 12!/(12 - 5)! = 12!/7! = (12 x 11 x 10 x 9 x 8 x 7!)/7! = 12 x 11 x 10 x 9 x 8 = 95,040 ways or The first student has 12 chances, the second students has 11 chances, the third student has 10 chances, the fourth student has 9 chances, and the fifth student has 8 chances. Thus, there are 95,040 ways (12 x 11 x 10 x 9 x 8) to chose five students from 12 students.
There are 12 ways to arrange 5 squares however i want to know what are the ways to do that! Can anybody help me too!!
The answer is 3C2*4C4*5C2 = [3 * 1 * (5*4)/(2*1)] = 3*1*10 = 30 ways.
It would be 5 ways
5 is. (How many different ways are there for him to notchoose one of the five ?)
There is a choice of 5 scarves, and for each scarf a choice of 10 pairs of shoes, giving 5 × 10 = 50 ways.
There are 8 ways to choose the first book There are 7 ways to choose the second book - 8 x 7 = 56 ways to select two books There are 6 ways to choose the third book - 8 x 7 x 6 = 336 way to select three books There are 5 ways to choose the fourth book - 8 x 7 x 6 x 5 = 1,680 ways to select four books.