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12
there are many answers. you need to know how many sides are on the dice
12 ways.
The sums divisible by 3 are 3, 6, 9 and 12. These can be obtained in 2, 5, 4 and 1 ways respectively, giving 2 + 5 + 4 + 1 = 12 ways of success. There are 36 possible ways two dice can fall → probability = ways_of_success/possible_ways = 12/36 = 1/3.
It would be 5 ways