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How many ways can a student select 7 questions from an exam containing 11 questions if he must answer the last question?
If he must answer the last question, he effectively needs to select 6 from 10. This can be done in 10C6 = 10*9*8*7/(4*3*2*1) = 210 ways.
How many ways can a student select 5 questions from an exam containing twelve questions if he must select the last question?
If he must include the last question, then his choices really boil down tohow many ways he can select 4 more from the remaining 11.The number of ways he can select 4 from 11 is (11 x 10 x 9 x 8) = 7,920 ways .But each group of 4 can be selected in 24 different ways.So he can only wind up with 7920/24 = 330 different groups of questions.
How many ways can 10 stand in a line?
10 people can line up in (10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2) = 3,628,800 different ways.
In how many ways can you arrange of the letter PHILIPPINES?
Assuming the Ps and Is are indistinguishable: There are 10! / 3! / 3! = 100800 ways If the Ps and Is are distinguishable, then there are 10! = 3628800 ways
How many ways are there to make 45 cents out of 15 10 5?
There are 13 ways.
How many ways can Aquiel select 4 books to buy form the 10 best sellers and read them?
Aquiel can select 4 books out of 10 best sellers, which can be done in 10 choose 4 ways, also denoted as "10C4" or "10 choose 4". This would result in 210 different ways for Aquiel to select and read the 4 books.
How many ways can a student select 7 questions from an exam containing 11 questions if he must answer the last question?
If he must answer the last question, he effectively needs to select 6 from 10. This can be done in 10C6 = 10*9*8*7/(4*3*2*1) = 210 ways.
In how many ways can a committee of three men and four women be formed from a group of 10 men and 10 women?
I'm going with 25,200 3 men out of 10 may be chosen in 10C3 ways = 10 ! / 3! 7 ! = 120 ways. 4 women may be chosen out of 10 in 10C4 = 10 ! / 4! 6! ways = 210 ways. Therefore, a committee with 3 men and 4 women can be formed in 120 x 210 = 25,200 ways.
How many ways can a student select 5 questions from an exam containing twelve questions if he must select the last question?
If he must include the last question, then his choices really boil down tohow many ways he can select 4 more from the remaining 11.The number of ways he can select 4 from 11 is (11 x 10 x 9 x 8) = 7,920 ways .But each group of 4 can be selected in 24 different ways.So he can only wind up with 7920/24 = 330 different groups of questions.
How many ways can you make 1 dollar using 5 cents 20 cents and 50 cents?
10 ways.10 ways.10 ways.10 ways.
What is the probability of 1 to 50 at random selecting numers with 4 in the 10 place?
The answer depends on how many numbers you select!The answer depends on how many numbers you select!The answer depends on how many numbers you select!The answer depends on how many numbers you select!
A teacher has 10 boys and 16 girls in her class In how many ways can she select 8 of the children to be in a play if she must select 4 boys and 4 girls?
She can select 210 different groups of boys and 1820 different groups of girls giving, wait for it, 382200 possible casts!
How many ways can 5 people be selected out of 10?
The number of ways is 10C5 = 10!/(5!*5!) = 10*9*8*7*6/(5*4*3*2*1) = 252
How many different ways can you arrange 10 books?
10!
How many ways can you make 15p?
There are several ways to make 15p using different combinations of coins. One way is to use one 10p coin and one 5p coin. Another way is to use three 5p coins. Additionally, you could use a combination of one 10p coin and five 1p coins. In total, there are multiple combinations that can add up to 15p.
How many ways can a person select 10 shirts from a collection of 14 shirts?
There are 1 001 ways a person may select 10 shirts from a collection of 14. To calculate this result you use the expression: 14C10 = 14!/[10!∙(14-10)!] where the symbol !, stands for factorial, such that: n! = n∙(n-1)∙(n-2)∙(n-3)∙,,,∙(4)∙(3)∙(2)∙(1) e.g., 5! = 5x4x3x2x1 = 120 The expression 14C10 will give the number of different 10 entity combinations you can make from a collection of 14 different entities.
How many ways can 10 stand in a line?
10 people can line up in (10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2) = 3,628,800 different ways.
