30240
There are 14C8 = 14*13*12*11*10*9/(6*5*4*3*2*1) = 3003 ways.
10 ways.10 ways.10 ways.10 ways.
5 for 2, 3 for 3, 2 for 4.
Assuming that zero cannot be used for the first digit then this can be selected from numbers 1 - 9 (9 choices), and the 2nd, 3rd and 4th digits from 0 - 9 (10 choices). The total number of different ways is : 9 x 10 x 10 x 10 = 9000.
30240
(5x4x3)/(3x2x1) = 10
There are 14C8 = 14*13*12*11*10*9/(6*5*4*3*2*1) = 3003 ways.
12C3 = 12*11*10/(3*2*1) = 220
240
Explanatory AnswerA team of 6 members has to be selected from the 10 players. This can be done in 10C6 or 210 ways.Now, the captain can be selected from these 6 players in 6 ways.Therefore, total ways the selection can be made is 210*6 = 1260.Alternatively, we can select the 5 member team out of the 10 in 10C5 ways = 252 ways.The captain can be selected from amongst the remaining 5 players in 5 ways.Therefore, total ways the selection of 5 players and a captain can be made = 252*5 = 1260.
10 ways.10 ways.10 ways.10 ways.
5 for 2, 3 for 3, 2 for 4.
Around 10 lakh people appeared for IIT 2010. But only 9000 got selected.
Three students can be selected from 5 in (5 x 4 x 3) = 60 ways.BUT there are (3 x 2) = 6 ways to select the same 3 students.So there are only 60/6 = 10 different groups of 3 studentsthat can be selected from a pool of 5.
The answer is 12C5 = 12*11*10*9*8/(5*4*3*2*1) = 792
-6