There are an infinite amount of ways.
There are 11!/[2!*2!*2!) = 4,989,600 ways.
4! 4 * 3 * 2 = 24 ways ==========
4! = 4*3*2*1 = 24 ways
3! = 1 x 2 x 3 = 6 ways.
24
You can arrange 4 in 2 ways 1x4 and 2x2.
There are 7!/(2!*2!*2!) = 630 ways.
There are 11!/[2!*2!*2!) = 4,989,600 ways.
4! 4 * 3 * 2 = 24 ways ==========
2 rows of 18 squares3 rows of 12 squares4 rows of 9 squares6 rows of 6 squares9 rows of 4 squares12 rows of 3 squares18 rows of 2 squares36 rows of 1 squareI would not count "1 row of 36 squares", because you only have a single row that cannot equal another row (there is only one rowafter all). If this is for homework, I would state your reasoning for excluding (or including) that set. Count all the options up, and you have 8 different ways you can arrange the rows with the exclusion.
30 ways.
3*2*1 = 6 ways.
There are 6!/2! = 360 ways.
4! = 4*3*2*1 = 24 ways
3! = 1 x 2 x 3 = 6 ways.
24
Choose 3 then 2 then 1; 3*2*1 = 6 ways.