Choose 3 then 2 then 1; 3*2*1 = 6 ways.
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To arrange 3 algebra books and 3 geometry books on a shelf so that no two books of the same type are next to each other, you can use the concept of permutations. There are 3! ways to arrange the algebra books and 3! ways to arrange the geometry books. This gives a total of 3! * 3! = 36 ways to arrange the books on the shelf such that no two books of the same type are next to each other.
Ill skip the factorials and just give you what the calculator does in the end. 8*7*6*5*4*3= 20,160
6 ways
12!/(5!*7!)The number of ways to arrange nitems is n!, where "!" is the factorial function. The number of ways we can arrange the 12 books is therefore 12!. However, we don't really care what order the first 5 books are in, or what order the last 7 books are in, as long as they're the same books. We therefore divide by the number of ways to arrange 5 books and the number of ways to arrange 7 books.