As always, we're going to ignore air resistance, and treat the question purely with
the math of free fall under the influence of gravity near the earth's surface.
The general equation for the free fall distance in time 'T' is: D=1/2 G T2 .
In this case, D=1 inch or 1/12th foot. 'G' is the acceleration of gravity = 32.2 ft/sec2 .
1/12 = 1/2 (32.2) T2
T2 = 1/(6 x 32.2) = 1/193.2
T = 71.9 milliseconds (rounded)
1/4 inch per foot.
Since one foot is 12 inches a four percent slope is .04X12 = 0.48 inch drop
One psi (pounds per square inch) is 27.7 inches of water. An inch of water is a unit of pressure which will raise water one inch. A cubic inch of water weighs 0.0361 pounds, so one psi is one over 0.0361 or 27.7 inches of water.
30.55 gallons (rounded) for every inch the water in the tub is deep.
One eighth inch drop per foot of run.
There would only be about an inch of water in a given area.
The correct fall for a 4 inch/100mm foul drain is 12.5mm per meter.. or 10mm per meter on a surface water drain
This problem lies with your pipe sizes. If the pipes size of your main line does not equal the supply for demand this will result in the current problem. For example, if your whole house is fed with half inch piping and you open two taps the volume of water has to be shared from the half inch pipe, thus causing a drop in pressure. Whereas if one installed three quarter inch main line "t-ing" off to half inch, because the three quarter inch will hold a higher volume of water when two taps are opened and the water shared, the drop in pressure will be hardly noticeable.
One inch of rain falling on one acre of land is equivalent to approximately 27,154 gallons of water.
1/8 inch fall for every foot of run is the ICC code minimum, but I would prefer 1/4 inch fall.
1/4 inch per foot.
1/8" per foot.
You don't
If all the water vapor in the Earth's atmosphere were to condense and fall to the ground, it would cover the globe with about 1 inch (2.5 cm) of water. This would equate to approximately 1/25th of an inch (1 mm) if evenly distributed over the entire surface of the Earth.
~0.0361 PSI per inch of height 0.0361PSI * 12 inches * 200 Feet = 86.64PSI
The difference between the length and the weight is called the "drop"; so a 34 inch bat that weighs 24 ounces would be a drop 10
1/8 inch per foot