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As always, we're going to ignore air resistance, and treat the question purely with

the math of free fall under the influence of gravity near the earth's surface.

The general equation for the free fall distance in time 'T' is: D=1/2 G T2 .

In this case, D=1 inch or 1/12th foot. 'G' is the acceleration of gravity = 32.2 ft/sec2 .

1/12 = 1/2 (32.2) T2

T2 = 1/(6 x 32.2) = 1/193.2

T = 71.9 milliseconds (rounded)

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Q: How milliseconds does it a drop of water to fall 1 inch?
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