The diagonal 'D' of the rectangle is the hypotenuse of a right triangle, whose legs are the rectangle's width 'W' and height 'H'. According to old Pythagoras: D2 = W2 + H2 D = sqr-root (W2 + H2) = sqr-rt(62 + 82) = sqr-rt(36 + 64) = sqr-rt(100) = 10 In a rectangle, the diagonals are equal, so their sum is 2D = 20.
231 m2 is about 2,486.5 square feet.
£15.45p but this may increase in future years.
sqr(-30) is i*sqr(30) We use i to represent the sqr(-1) because it is called an imaginary number. It takes an imagination to work with it. It is not fictitious.
54 = 625 (to find out sqr rt 625 then sqr rt again)
You can't convert that.
1 decimal is how much sqr meeter
8(1st eight) +8(2nd eight)= 16-> sqr(16)=4 -> sqr(4)=2 ; 8(3rd eight)-2=6
The sin of 30 is sqr(3)/2 so 6 * sqr(30) is 6 * sqr(3)/2 this is also 6/2 * sqr(3) which simplifies to 3 * sqr(3) which is approximately 5.19615242
The diagonal 'D' of the rectangle is the hypotenuse of a right triangle, whose legs are the rectangle's width 'W' and height 'H'. According to old Pythagoras: D2 = W2 + H2 D = sqr-root (W2 + H2) = sqr-rt(62 + 82) = sqr-rt(36 + 64) = sqr-rt(100) = 10 In a rectangle, the diagonals are equal, so their sum is 2D = 20.
Area is not measured in centimeter units. It may be guessed that the question should have indicated the area in square centimeters.The area of a regular pentagon is given as:A = s * s * sqr(25 + 10*(sqr(5)) / 4Solve for s:s = 2 * sqr (A / sqr(25 + 10*(sqr(5)))Insert the area of 600 square centimters:s = 2 * sqr (600 cm*cm / sqr(25 + 10*(sqr(5)))s = aproximately 19.67 cm
231 m2 is about 2,486.5 square feet.
£15.45p but this may increase in future years.
sqr(-30) is i*sqr(30) We use i to represent the sqr(-1) because it is called an imaginary number. It takes an imagination to work with it. It is not fictitious.
x=81
110
x=81