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Q: How much can be placed on a circular serving tray that has a diameter of 18 in?

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Approx. 408.4 feet.

1154 pesos for the top rounded to the nearest peso.

You have given three things:Mean diameter = 12cm , r=6cmDiameter of circular gold wire = 3mm =.3cm, r=.15cm20gm gold in 1 cubic centimeterNow simply, you have a diameter of gold wire take the radius that is .15 cm and find the area of the circular wire - A=πr^2=π0.15^2=0.0706sq.cmNow you have the diameter of the bangle that is 12cm and rad=6cmfind the circumference - c=2πr, c=2π6=37.699cmfor 4 bangles 37.699 x 4=150.79 cubic centimeterto get volume multiply area of circular wire with circumference that isA x C=150.79 x 0.0706=10.656cubic centimeterNow you know 1cm^3 has 20 gm of goldthen 10.656cm^3 cube will have20 x 10.656cm^3=213.183 grams!

The diameter is twice as large as the radius.

The equation for the perimeter of a circle is the mathematical constant PI times the diameter of the circle. PI is an irrational number that is approximated by 3.141592653, or some times 3.14. C = PI * D In your case: C = 3.14 x 32 (feet) C = 100.48 feet You can figure the rest!

Related questions

A circular tank is 12 meter in diameter and 7.5 meter in height. how much water does it hold when half full?

i need help

Approx. 408.4 feet.

A length of approx 18.85 feet.

Length of edging required = Circumference of tablecloth = pi*diameter = pi*1 metres = pi metres. So approx 3.1416 metres.

The cross-sectional area is one of the factors that determines how much current a conductor can carry -this is regardless of the shape of that conductor's cross section (many conductors are not circular). So the diameter is of not much interest.

The answer is 1373.75

The answer is 1373.75

The answer is 1373.75

You may be thinking of a Fresnel Lens. This is a lens of large diameter, but which is made to be compact size and weight by consisting of a series of concentric circular prisms. This still behaves as a large diameter lens, but with much reduced mass.

1154 pesos for the top rounded to the nearest peso.

You have given three things:Mean diameter = 12cm , r=6cmDiameter of circular gold wire = 3mm =.3cm, r=.15cm20gm gold in 1 cubic centimeterNow simply, you have a diameter of gold wire take the radius that is .15 cm and find the area of the circular wire - A=πr^2=π0.15^2=0.0706sq.cmNow you have the diameter of the bangle that is 12cm and rad=6cmfind the circumference - c=2πr, c=2π6=37.699cmfor 4 bangles 37.699 x 4=150.79 cubic centimeterto get volume multiply area of circular wire with circumference that isA x C=150.79 x 0.0706=10.656cubic centimeterNow you know 1cm^3 has 20 gm of goldthen 10.656cm^3 cube will have20 x 10.656cm^3=213.183 grams!