10
(are, not 'r')
The area of a semicircle can be calculated using the formula ( A = \frac{1}{2} \pi r^2 ), where ( r ) is the radius. Since the diameter is given as ( Cm ), the radius ( r ) is ( \frac{Cm}{2} ). Plugging this into the formula gives ( A = \frac{1}{2} \pi \left(\frac{Cm}{2}\right)^2 = \frac{\pi (Cm)^2}{8} ). Thus, the area of the semicircle is ( \frac{\pi (Cm)^2}{8} ).
The circumference of a circle of radius r cm is 2*pi*r cm so the length of the semi-circular arc is pi*r cm. The length of the diameter is 2*r cm so the total length is (pi + 2)*r cm
The volume ( V ) of a right cone can be calculated using the formula ( V = \frac{1}{3} \pi r^2 h ), where ( r ) is the radius and ( h ) is the height. Given the base diameter of 10 cm, the radius ( r ) is 5 cm. Substituting the values, the volume is ( V = \frac{1}{3} \pi (5^2)(9) = \frac{1}{3} \pi (25)(9) = 75\pi ) cm³, which is approximately 235.62 cm³.
The formula for finding the volume of a cone is 1/3(pi)(r)(r)(h) where r is the radius and his the height, or in your case, 1/3(B)(h) where B is the area of the base and h is the height since part of the original formula is finding the base area [(pi)(r)(r)]. Plug your measurements into your calculator and you get 76 2/3 pi square cm, or 240.7 square cm.
The area of a circle with radius r is pi*r*r where pi = 3.1416 approx. When r = 6 cm, the area is 113.1 sq cm.
Assuming the pipe is circular in profile, then it makes the shape a cylinder. Hence volume (cyl) = pi r^2 h pi = 3.141592..... r = 26 mm = 2.6 cm h = 1.0 = 100 cm Hence substiting. V(cyl) = 3.131592... (2.6)^2 x 100 V = 2123.716634 cm^3 = There being 1000 cm^2 in 1 litre (1 dm^3) Hence vol = 2.123716634 L V =~ 2.12 L is the amount of water in the pipe.
we know circumference=2*pi*r; where r=1; circumeference=2*3.14*1=6.28 cm
Remember for the volume of a cone, the eq'n is V(cone) = (1/3) pi r^(2) h Algebraically rearrange r^(2) = 3V/(pi*h). r = sqrt[ 3V/(pi*h)] Substituting r = sqrt[3(400cm^(3)/(3.141592...*8.5 cm)]. r = sqrt[(1200cm^(3) / 26.70353756....cm) r = sqrt[44.93786628... cm^(2)] r = 6.703571159....cm t ~ 6.7 cm ( 1 d.p.) NB Units (cm) have been included to show how cm^(3) ( volume) is reduced to 'cm'. (linear). NNB Also don't forget, as a last step, to square root both sides.
A=Pirh 550cm = Pi (r) 24cm 550/ Pi (24) = r r = 7.3 cm V= 1/3 Pi r^2 h V= 1/3 Pi (7.3)^2 (24) V= 1339.32cm^3
The area of a semicircle can be calculated using the formula ( A = \frac{1}{2} \pi r^2 ), where ( r ) is the radius. Since the diameter is given as ( Cm ), the radius ( r ) is ( \frac{Cm}{2} ). Plugging this into the formula gives ( A = \frac{1}{2} \pi \left(\frac{Cm}{2}\right)^2 = \frac{\pi (Cm)^2}{8} ). Thus, the area of the semicircle is ( \frac{\pi (Cm)^2}{8} ).
The circumference of a circle of radius r cm is 2*pi*r cm so the length of the semi-circular arc is pi*r cm. The length of the diameter is 2*r cm so the total length is (pi + 2)*r cm
The volume ( V ) of a right cone can be calculated using the formula ( V = \frac{1}{3} \pi r^2 h ), where ( r ) is the radius and ( h ) is the height. Given the base diameter of 10 cm, the radius ( r ) is 5 cm. Substituting the values, the volume is ( V = \frac{1}{3} \pi (5^2)(9) = \frac{1}{3} \pi (25)(9) = 75\pi ) cm³, which is approximately 235.62 cm³.
gosh how old r ya? it's 100cm's
The formula for finding the volume of a cone is 1/3(pi)(r)(r)(h) where r is the radius and his the height, or in your case, 1/3(B)(h) where B is the area of the base and h is the height since part of the original formula is finding the base area [(pi)(r)(r)]. Plug your measurements into your calculator and you get 76 2/3 pi square cm, or 240.7 square cm.
If the radius is r cm and the height is h cm, then Volume = pi*r^2*h cm^3 and Surface area = 2*pi*r(r+h) cm^2
The area of a circle with radius r is pi*r*r where pi = 3.1416 approx. When r = 6 cm, the area is 113.1 sq cm.
To find the rate at which the radius is increasing when the radius is 3 cm, we use the formula for the area of a semicircle, ( A = \frac{1}{2} \pi r^2 ). Differentiating with respect to time, we have ( \frac{dA}{dt} = \pi r \frac{dr}{dt} ). Given ( \frac{dA}{dt} = 1 ) cm²/sec and ( r = 3 ) cm, we can substitute to find ( 1 = \pi (3) \frac{dr}{dt} ), leading to ( \frac{dr}{dt} = \frac{1}{3\pi} ) cm/sec. Thus, the radius is increasing at a rate of approximately 0.106 cm/sec when the radius is 3 cm.