80 ft deep? by 2 ft wide by what other required dimension.
Volume requires 3 dimensions.
The volume would be calculated from the Volume = base_area * height.
Assuming by 2 feet wide you mean a circular base of 2 feet in diameter, base area of a circle is simply the familiar pi * radius-squared, where the radius is half of the diameter. This gives approximately PI * 1 ft * 1 ft, or PI square-feet, approximately 3.1416 square-feet. Now take this base area and multiply times your height, 80 ft.
Go ahead, you can at least find the solution from the last step. Answer will be in cubic feet (feet^3).
There is none. Because there is a hole! If you are asking how much dirt can fill the hole, then your answer is 27 cubic feet.
There's no dirt in a hole.
None
none
There is 98.17477042 cubic feet of dirt in a 5 foot deep hole that is 5 foot across.
There is none. Because there is a hole! If you are asking how much dirt can fill the hole, then your answer is 27 cubic feet.
There's no dirt in a hole.
a lot of dirt.
There's no dirt in a hole.
None
There is no dirt in a hole because a hole is defined by the absence of material, in this case dirt. If you were to fill the hole with dirt, it would require 24 cubic feet of dirt to completely fill it.
none
There is 98.17477042 cubic feet of dirt in a 5 foot deep hole that is 5 foot across.
None. If it's a hole, then the dirt has been removed.
None it's a hole
2720'³
24 feet