Nine of them.
Two thousand
7.4120
There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }
212300 ones
No, it does not.
Nine of them.
4000 of them.
Seven of them.
Eight of them.
Two thousand
70000
_?_thousands =3000 ones
50000
7.4120
89,275 80,000 = 8 x 10,000 7,000 = 7 x 1,000 2,200 = 22 x 100 70 = 7 x 10 5 = 5 x 1
65