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Q: How much is 6 tens and 5 ones regrouping though thousands?
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What is regrouping in math?

EXAMPLE: 24+2= 26 NO REGROUPING 56+3=59 NO REGROUPING 24+8=32 IS REGROUPING 56+4=60 IS REGROUPING TAKING THE ONES PLACE ONLY: FIRST EXAMPLE 4+2=6 HAS TO BE LESS THAN 9 4+8=12 YOU MAKE 10 IN THE ONES PLACE YOU CARRY OVER WHICH NOW THEY ARE CALLING REGROUPING. WE JUST CALLED IT CARRYING OVER AND BORROWING. HOPE THIS HELPS.


How much does 212.3 thousands equal in ones?

How much does 147 thousands equal in millions


What do you write to show Regrouping 10 ones as 1 ten?

one 10


How do you regroup in additon?

Back in the day, regrouping in addition was called "carrying" and regrouping in subtraction was called "borrowing." I think "regrouping" is a better term for all of it. This problem might be easier to visualize if you copy it vertically. Example: 45 + 28 5 + 8 is 13, which won't fit in the ones place, so we leave 3 of the ones there and regroup the ten other ones into one ten which we add in the tens column. 1 + 4 + 2 = 7 45 + 28 = 73


What numbers can be added to 21 that would require regrouping in the ones place?

9, 29, 39, 49,59,69,79,89,99.............etc


What is the meaning of addition with carrying?

Back in the day, regrouping in addition was called "carrying" and regrouping in subtraction was called "borrowing." I think "regrouping" is a better term for all of it. These problems might be easier to visualize if you copy them vertically. Example: 45 + 28 5 + 8 is 13, which won't fit in the ones place, so we leave 3 of the ones there and regroup the ten other ones into one ten which we add in the tens column. 1 + 4 + 2 = 7 45 + 28 = 73


How much is 13 thousands 5 hundreds 27 tens 19 ones?

13789


Is regrouping a method in math?

Back in the day, regrouping in addition was called "carrying" and regrouping in subtraction was called "borrowing." I think "regrouping" is a better term for all of it. These problems might be easier to visualize if you copy them vertically. Example: 56 - 39 Just looking at it, you might think there's a problem with subtracting nine from six until you realize that 56 is 5 tens and 6 ones which is the same thing as 4 tens and 16 ones. Now you can subtract 9 from 16, leaving 7 in the ones place and 3 from 4, (the regrouped 5) leaving 1 in the tens place. 56 - 39 = 17 Example: 45 + 28 5 + 8 is 13, which won't fit in the ones place, so we leave 3 of the ones there and regroup the ten other ones into one ten which we add in the tens column. 1 + 4 + 2 = 7 45 + 28 = 73


You are a four digit number your ones is twice your tens your hundreds is five less than your ones your thousands place is the sum of your tens and hundreds what number are you?

There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }


What is subrtacting with regrouping in whole numbers?

Back in the day, regrouping in addition was called "carrying" and regrouping in subtraction was called "borrowing." These problems might be easier to visualize if you copy them vertically. Example: 56 - 39 Just looking at it, you might think there's a problem with subtracting nine from six until you realize that 56 is 5 tens and 6 ones which is the same thing as 4 tens and 16 ones. Now you can subtract 9 from 16, leaving 7 in the ones place and 3 from 4, (the regrouped 5) leaving 1 in the tens place. 56 - 39 = 17


How many ones in 212.3 thousands?

212300 ones


How many thousands are in 900 ones?

900 is 0.9 thousands.