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2.48 X 10^-17 J
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That depends on the mass, pressure, and temperature of the air in the cubic meter.
It depends. The longer you leave the lights on and the more you flush the toilet, the more energy consumption you will have.
The wavelength will increase if the period increases.Proof:First define the terms: Wavelength = Lamda (λ), Velocity of propagation = v, frequency = f, period of oscillation = T. Frequency asks "how many waves per unit time (seconds usually)".Period asks "How much time (seconds) does it take for one wave cycle to complete".Also, frequency is inversely proportional to period, so f = 1/T. Also, T = 1/f.(Incidentally, note that as period (T) increases, then frequency (f) gets decreases. Or if frequency increases, then period decreases.)λ = v/forλ = vT. (by replacing f with 1/T)If the frequency decreases, OR/AND the velocity increases, then wavelength corespondingly increases.If the period increases OR/AND the velocity increases, then the wavelength increases.
The energy is 18,263.10e4 joules.
The energy of a photon of green light with a wavelength of approximately 520 nanometers is about 2.38 electronvolts.
Yes, due to the energy of photons/electromagnetic particles being determined by the equations below: E= hv=hc(1/v)= hc/wavelength. Where E= energy, v= frequency in Hz, h= Planck's constant, c= speed of light Electrons have a very short wavelength, and a very high frequency, thus they have much more energy than a beam of light.
To calculate the energy of photons, you can use the equation E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength. First, convert the wavelength to meters (655 nm = 655 x 10^-9 m). Plug the values into the equation to find the energy per photon, and then multiply by Avogadro's number to get the total energy for 3.0 moles of photons.
To calculate the energy of X-ray photons, we use the formula E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength of the photon in meters. First, we convert the wavelength from nanometers to meters: 0.135 nm = 0.135 x 10^-9 m. Now we can plug these values into the formula: E = (6.626 x 10^-34 J s * 3 x 10^8 m/s) / (0.135 x 10^-9 m) = 4.65 x 10^-15 J per photon.
Each photon in it has 2.483 x 10-17 joule of energy.You can flood the patient with as much total energy as you think he needsby blasting him with enough photons.
The longer the wavelength of light, the smaller its frequency, and the less energy there is for every photon.
No, microwave photons have less energy than photons of visible light. The energy of a photon is directly proportional to its frequency, where higher frequency photons have higher energy. Microwave photons have lower frequencies than visible light photons, so they have less energy.
Stokes shift indicates the energy difference between the absorption and emission of light by a molecule. It is commonly used in fluorescence spectroscopy to determine the wavelength shift and provides information about the electronic transitions occurring in the molecule.
Energy varies with the wavelength. The shorter the wavelength the higher the energy. Ultraviolet much more energetic than red light.
Yes, gamma rays are a form of electromagnetic radiation that have the highest energy and shortest wavelength in the electromagnetic spectrum. They are often referred to as high-energy photons or light.
The energy of a photon of ultraviolet radiation is greater than the energy of an average photon of sunlight because ultraviolet radiation has higher frequencies and shorter wavelengths, which correspond to higher energy photons. The difference in energy can be significant, with ultraviolet photons having several times more energy than photons of sunlight.