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The energy of a photon can be calculated using the equation ( E = \frac{hc}{\lambda} ), where ( E ) is the energy, ( h ) is Planck's constant (( 6.626 \times 10^{-34} ) J·s), ( c ) is the speed of light (( 3.00 \times 10^8 ) m/s), and ( \lambda ) is the wavelength in meters. For a wavelength of ( 2.49 \times 10^{-5} ) nm (or ( 2.49 \times 10^{-14} ) m), the energy is approximately ( 8.03 \times 10^{-15} ) joules, which is equivalent to about 50.1 keV.

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5d ago

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How do you calculate how much energy in kJ do 3.0 moles of photons all with a wavelength of 655 nm contain?

The energy is 18,263.10e4 joules.


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Yes, due to the energy of photons/electromagnetic particles being determined by the equations below: E= hv=hc(1/v)= hc/wavelength. Where E= energy, v= frequency in Hz, h= Planck's constant, c= speed of light Electrons have a very short wavelength, and a very high frequency, thus they have much more energy than a beam of light.


How much energy in kJ do 3.0 moles of photons all with a wavelength of 655 nm contain?

To calculate the energy of photons, you can use the equation E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength. First, convert the wavelength to meters (655 nm = 655 x 10^-9 m). Plug the values into the equation to find the energy per photon, and then multiply by Avogadro's number to get the total energy for 3.0 moles of photons.


How much energy is contained in 1 rm mol of each of the following X-ray photons with a wavelength of 0.135 rm nm?

To calculate the energy of X-ray photons, we use the formula E = hc/λ, where h is Planck's constant (6.626 x 10^-34 J s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength of the photon in meters. First, we convert the wavelength from nanometers to meters: 0.135 nm = 0.135 x 10^-9 m. Now we can plug these values into the formula: E = (6.626 x 10^-34 J s * 3 x 10^8 m/s) / (0.135 x 10^-9 m) = 4.65 x 10^-15 J per photon.


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A microwave signal at 50 GHz has waves that are 10,000 times as long as a visible signal at yellow (600 nm) has. Therefore the yellow photon carries 10,000 times as much energy as the 50 GHz photon does.


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Energy varies with the wavelength. The shorter the wavelength the higher the energy. Ultraviolet much more energetic than red light.


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