Wiki User
∙ 11y ago538J
Wiki User
∙ 11y agoThat completely depends on the specific heat capacity of the substance of which the sample is composed, which you haven't identified. It will take a lot more heat energy to raise the temperature of 65 grams of water 35 degrees than it would take to do the same to 65 grams of iron or yogurt, e.g.
heat will flow from the iron to the water until both are the same temperature
Temperature isn't governed by weight so both can have the same temperature. Do you mean which has a higher melting point? That's iron as silver melts at a lower temperature.
1 cubic foot of iron, at room temperature would weigh approx 2190 newtons.
The density of iron (at room temperature) is approx 7.87 grams/cm3. Therefore, volume of 63.6 grams = 8.08 cm3
The specific heat capacity of iron is 0.45 J/g°C. To calculate the energy required to raise the temperature of 2 kg of iron by 3 degrees Celsius, you can use the formula: Energy = mass x specific heat capacity x temperature change. Plug in the values to find the answer.
The specific heat capacity of iron is 0.45 J/g°C. To calculate the energy required, you can use the formula: Energy = mass x specific heat capacity x change in temperature. Plugging in the values, Energy = 5g x 0.45 J/g°C x (30°C - (-10°C)). This calculation would give you the energy in joules required to raise the temperature of 5 grams of iron from -10ºC to 30ºC.
The specific heat capacity of iron is 0.45 J/g°C. Therefore, the energy required to raise the temperature of 3 kg (3000 g) of iron by 3°C is calculated as follows: Energy = mass x specific heat capacity x temperature change. Plugging in the values, we get Energy = 3000g x 0.45 J/g°C x 3°C = 4050 Joules.
The formula is: 0,108 x 3000 x (T1 -T2), in kilocalories.
The amount of energy required to raise the temperature of a substance can be calculated using the formula: energy = mass x specific heat capacity x temperature change. For iron, the specific heat capacity is 0.449 J/g°C. Assuming the temperature change is 1°C, the energy required would be 3 kg x 1000 g/kg x 0.449 J/g°C = 1347 J.
The specific heat capacity of iron is 0.45 J/g°C. To raise the temperature of 3kg (3000g) of iron by 5 degrees Celsius, you would need: 3000g x 0.45 J/g°C x 5°C = 6750 Joules of energy.
Iron would require a greater amount of heat to raise its temperature compared to water. This is because iron has a higher specific heat capacity, meaning it takes more heat energy to increase its temperature by 1 degree Celsius compared to water.
The specific heat capacity of iron is 0.45 J/g°C. To find the energy required to raise the temperature of 2kg of iron from 20°C to 23°C, you would use the formula: Energy = mass x specific heat capacity x change in temperature. So, Energy = 2,000g x 0.45 J/g°C x (23°C - 20°C). Calculate this to find the energy required.
1935 J
38 cal
To calculate the energy released to raise the temperature of 2kg of iron from 20 to 23 degrees Celsius, you would use the formula: Energy = mass x specific heat capacity x temperature change. The specific heat capacity of iron is approximately 0.45 J/g°C. First, convert 2kg to 2000g. Then calculate the energy released using these values.
The specific heat capacity of iron is about 0.45 J/g°C. To raise the temperature of 3 kg of iron by 5°C, you would use the equation Q = mcΔT, where m is the mass (3 kg), c is the specific heat capacity (0.45 J/g°C), and ΔT is the change in temperature (5°C). Therefore, the energy required would be around 6,750 Joules.