538J
That completely depends on the specific heat capacity of the substance of which the sample is composed, which you haven't identified. It will take a lot more heat energy to raise the temperature of 65 grams of water 35 degrees than it would take to do the same to 65 grams of iron or yogurt, e.g.
To calculate the calories required to change the temperature of iron, use the formula ( Q = mc\Delta T ), where ( m ) is the mass (25.5 g), ( c ) is the specific heat capacity of iron (approximately 0. iron 0.45 J/g°C or 0.11 cal/g°C), and ( \Delta T ) is the change in temperature (83.2°C - 22.5°C = 60.7°C). Thus, ( Q = 25.5 , \text{g} \times 0.11 , \text{cal/g°C} \times 60.7°C \approx 188.5 , \text{cal} ). Therefore, approximately 188.5 calories are required to change the temperature of 25.5 g of iron from 22.5°C to 83.2°C.
heat will flow from the iron to the water until both are the same temperature
Temperature isn't governed by weight so both can have the same temperature. Do you mean which has a higher melting point? That's iron as silver melts at a lower temperature.
1 gram of iron contains less energy than 1 gram of water primarily due to the difference in their specific heat capacities. Water has a high specific heat capacity (about 4.18 J/g°C), meaning it can store more thermal energy per gram per degree of temperature change. In contrast, iron has a lower specific heat capacity (about 0.45 J/g°C), indicating it can store significantly less thermal energy under the same conditions. This difference results in water having a greater energy content for the same mass compared to iron.
The specific heat capacity of iron is 0.45 J/g°C. To calculate the energy required to raise the temperature of 2 kg of iron by 3 degrees Celsius, you can use the formula: Energy = mass x specific heat capacity x temperature change. Plug in the values to find the answer.
The specific heat capacity of iron is 0.45 J/g°C. To calculate the energy required, you can use the formula: Energy = mass x specific heat capacity x change in temperature. Plugging in the values, Energy = 5g x 0.45 J/g°C x (30°C - (-10°C)). This calculation would give you the energy in joules required to raise the temperature of 5 grams of iron from -10ºC to 30ºC.
The formula is: 0,108 x 3000 x (T1 -T2), in kilocalories.
The specific heat capacity of iron is 0.45 J/g°C. Therefore, the energy required to raise the temperature of 3 kg (3000 g) of iron by 3°C is calculated as follows: Energy = mass x specific heat capacity x temperature change. Plugging in the values, we get Energy = 3000g x 0.45 J/g°C x 3°C = 4050 Joules.
The amount of energy required to raise the temperature of a substance can be calculated using the formula: energy = mass x specific heat capacity x temperature change. For iron, the specific heat capacity is 0.449 J/g°C. Assuming the temperature change is 1°C, the energy required would be 3 kg x 1000 g/kg x 0.449 J/g°C = 1347 J.
The specific heat capacity of iron is 0.45 J/g°C. To raise the temperature of 3kg (3000g) of iron by 5 degrees Celsius, you would need: 3000g x 0.45 J/g°C x 5°C = 6750 Joules of energy.
To raise the temperature of both an equal amount, water would require more energy. In terms of the energy required to raise the temperature: iron = 0.45 joules / gram . kelvin water = 4.2 joules / gram . kelvin This is known as the specific heat capacity of a material
The specific heat capacity of iron is 0.45 J/g°C. To find the energy required to raise the temperature of 2kg of iron from 20°C to 23°C, you would use the formula: Energy = mass x specific heat capacity x change in temperature. So, Energy = 2,000g x 0.45 J/g°C x (23°C - 20°C). Calculate this to find the energy required.
1935 J
38 cal
To calculate the energy released to raise the temperature of 2kg of iron from 20 to 23 degrees Celsius, you would use the formula: Energy = mass x specific heat capacity x temperature change. The specific heat capacity of iron is approximately 0.45 J/g°C. First, convert 2kg to 2000g. Then calculate the energy released using these values.
In heat.Because iron absorbs heat.