Hi,
In general when something becomes larger, the surface area to volume ratio decreases. The analogy of a cube is indeed a useful way to think about it. I'll try to put it in more general terms.
Cubes are a great example to talk about because their surface area and volume are really easy to calculate. The surface area of a cube is the length x the width x the number of sides (six sides, in the case of a cube). The volume of a cube is the length x width x volume.
So, say we have a cube with a side length of three. The surface area is going to be 3x3x6 = 54. The volume is going to be 3x3x3 = 27, for a ratio of 54:27, or 2:1
//Another contributor does not think you should make a ratio of different dimensions (area and volume)//
Surface area increases as the square of a dimension, volume increases as the cube of a dimension.
Example:A sphere (ball)
Diameter = 1 unit
Increase diameter to twice the size: New diameter = 2
Area of new sphere = 4 times the area of the initial sphere
Volume of the new sphere = 8 times the volume of the initial sphere
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They both increase. The rate of increase of the surface area is equivalent to the rate of increase of the volume raised to the power 2/3.
the volume increase 8 times
No. In fact, if they retain their combined volume, their surface area would increase.
A smaller cell has a higher surface area to volume ratio. A reason for this is volume is cubic (3D) and surface area is 2D so when surface area increases a little bit, the volume increases exponentially. And when the surface area shrinks a little bit, the volume decreases exponentially.
hippopatamus