Q = m*c*delta T
c for coal = 0.24 (depending on its origin)
Q = 5*0.24*(220-20) = 240 Joules
c for anthracite coal is also given as 0.201 which will give an answer of 201 Joules
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That would depend on the size of the room and the humidity.
question makes no sense.....
No BTU are required in order to lowerthe temperature of water. All you have to dois place the water in an environment that is cooler than the water is, then stand backand watch the temperatue of the water drop while the BTU flow out of it.
212F.
You just say "degree" followed by the temperature scale, for example, "It was 20 degrees Celsius".