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∙ 16y ago: ΔQ = mcΔT : ΔQ = (60g) (0.385 J g−1 K−1) (60 °C same as 60 Kelvin) : :: = 1386 Joules
Wiki User
∙ 16y agoq = (250 g)(0.46 J/gC)(300 C - 27 C) = 3.1 X 104 Joules -------------------------
The nagle of light determines the area over which the energy of the light is spread out and that will affect how much it is heated.
None. They are 75% copper and 25% copper.
1963 COPPER penny is worth half a billion dollars.
That completely depends on the specific heat capacity of the substance of which the sample is composed, which you haven't identified. It will take a lot more heat energy to raise the temperature of 65 grams of water 35 degrees than it would take to do the same to 65 grams of iron or yogurt, e.g.
The specific heat capacity of copper is 0.385 J/g°C. You can use the formula Q = mcΔT, where Q is the heat absorbed, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. Plugging in the values, you can calculate the heat absorbed by the copper.
The specific heat capacity of iron is 0.449 J/g°C. To calculate the heat absorbed, use the formula Q = mcΔT, where Q is the heat absorbed, m is the mass in grams, c is the specific heat capacity, and ΔT is the temperature change. Plugging in the values, the heat absorbed by 1.0 g of iron heated to 15°C is 6.735 J.
51%
Absorbed heat depends on the specific heat capacity of the substance. If you provide the substance and the temperature change, then we can help you calculate the heat absorbed.
A copper wire is a much better conductor of heat than air is.
To find the heat energy absorbed by the lead block, you need to use the specific heat capacity of lead, which is 128 J/kg°C. The formula to calculate heat energy is: Q = m * c * ΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. Plugging in the values, you can find the heat energy absorbed by the lead block.
The heat absorbed by the copper can be calculated using the equation Q = mcΔT, where Q is the heat absorbed, m is the mass of the copper, c is the specific heat capacity of copper (0.385 J/g°C), and ΔT is the change in temperature (353K - 293K = 60K). Plugging these values into the equation, we find Q = 60.00g * 0.385 J/g°C * 60K = 1395 J.
Solid copper appears to gain mass when heated in air, because the copper reacts with oxygen in the air to form copper oxide. However, the actual mass of the copper does not increase; the mass of the solid increases by a value equal to the mass of oxygen removed from the air.
q = mHvq = heatm = mass (30g)Hv = heat of vaporization (2,260J/g)q = (30g)(2,260J/g)q = 67,800JWhen 30 grams of water is converted into steam, how much heat is absorbed?67,800J of heat, also represented as 67.8kJ of heat is absorbed.
The heat absorbed during vaporization is called the heat of vaporization. For carbon tetrachloride, the heat of vaporization is 30.5 kJ/mol. To calculate the heat absorbed when 75 g of CCl4 vaporizes, you would first convert grams to moles using the molar mass of CCl4. Then, use the heat of vaporization to calculate the total heat absorbed.
It depend upon the temperature how much you heat it
all of them, just depends on how much heat you use