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: ΔQ = mcΔT : ΔQ = (60g) (0.385 J g−1 K−1) (60 °C same as 60 Kelvin) : :: = 1386 Joules

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Q: How much heat is absorbed by 60 g of copper when heated from 20 C to 80 C?
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How much heat is absorbed by 60.0 grams of copper when it is heated from 293 Kelvin to 353 kelvin?

The specific heat capacity of copper is 0.385 J/g°C. You can use the formula Q = mcΔT, where Q is the heat absorbed, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. Plugging in the values, you can calculate the heat absorbed by the copper.


How much heat is absorbed by 1.0 g of iron when its heated to 15 degrees celsius?

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How much heat is absorbed by 60.00 grams of copper when it is heated from 293 Kelvin to 353 Kelvin?

The heat absorbed by the copper can be calculated using the equation Q = mcΔT, where Q is the heat absorbed, m is the mass of the copper, c is the specific heat capacity of copper (0.385 J/g°C), and ΔT is the change in temperature (353K - 293K = 60K). Plugging these values into the equation, we find Q = 60.00g * 0.385 J/g°C * 60K = 1395 J.


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