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How many milligrams of salt must be added to 18 milligrams of a 20 percent salt solution to obtain a 35 percent salt solution?
this question is not hard to answer, but it does require that one make some assumptions. The simplest answer assumes that the 20% salt solution refers to per cent by mass. Thus: a 20% salt solution is one which contains 20 mg salt for every 100 mg solution where the solution consists of a mixture of 20 mg salt plus 80 mg water. A 35% salt solution would contain 35 mg salt for every 65 mg water. Now, assuming that all the water in 18 mg of a 20% salt solution remains in the final solution we see that 18 mg salt solution x 20 mg salt/100 mg salt solution gives 3.6 mg of salt; thus, there are 18 mg total solution - 3.6 mg salt = 14.4 mg water. So the final salt solution must be one that contains 14.4 mg water and enough salt to make it 35% salt by mass. Mathematically, this is written as Z mg salt/(Z mg + 14.4 mg water) = 35/100 This gives Z = 0.35*(Z + 14.4) or Z = 0.35*Z + 0.35*14.4 which is same as Z = 0.35*Z + 5.04 and 0.65*Z = 5.04 so Z = 5.04/0.65 = 7.75 mg total salt needed. We started with 3.6 mg salt, so we must add 7.75 -3.6 = 4.15 mg salt Check: 7.75 mg salt/(7.75 mg salt + 14.4 mg water) = 0.35 or 35% There you go! --assuming that much salt dissolves that amount of water!
2300 square feet is how much in square meters?
Answer: 2300 ft² = 213.676 m²
How many mg in 1 gram of salt?
1,000 1 gram = 1000 mg 1 mg = .001g
How much is 23kn in kilogram?
2300 kg
How many milligrams of sodium is in 1 teaspoon of table salt?
One teaspoon of table salt typically contains about 2,300 milligrams of sodium. This is because sodium chloride, the chemical name for table salt, is made up of about 40% sodium by weight. Therefore, in a 1 teaspoon serving of table salt, you would be consuming approximately 2,300 milligrams of sodium.
