45*20*20cm=
180,000 mm3
18,000 cm3
1,800 dm3
180 m3
18 Dm3
1.8 hm3
0.18 km3
* * * * *
18,000 cm3 is correct but all the other numbers are wrong.
1 cm = 10 mm so 1 cm3 = 10 mm * 10 mm * 10 mm = 1000 mm3
so the correct values are 18,000,000 mm3 or 0.018 m3.
And 1.8*10-11 km3 , the correct answer is a billionth of the rubbish given in the prvious answer!
The foil has a volume of 45 cm x 30 cm x 0.0010 cm = 1.35 cm3. Density is mass per unit volume, so with a density of 2.7g/cm3, 1 cm3 of aluminum will weigh 2.7g. Therefore 1.35 cm3 will weigh 2.7 x 1.35 = 3.645g
20 cm x 20 cm x 20 cm = 8,000 cm3
20 percent of 45 = (20 / 100) x 45 = 9.
45 x 20 ÷ 100 =9
45 x 0.2 = 9
2.25 x 20 = 45
The foil has a volume of 45 cm x 30 cm x 0.0010 cm = 1.35 cm3. Density is mass per unit volume, so with a density of 2.7g/cm3, 1 cm3 of aluminum will weigh 2.7g. Therefore 1.35 cm3 will weigh 2.7 x 1.35 = 3.645g
20 cm x 20 cm x 20 cm = 8,000 cm3
20 percent of 45 = (20 / 100) x 45 = 9.
Answer: 45% Work: 20 is decreased to 11 9 = D x 20 --- ---- 20 20 20 divided by 9 = .45 .45 as a percent = 45 %
Well 20% is 1/5 so to get to 100% you need to multiply by 5: 20% x 5 = 100% and 45 x 5 = 225
45 x 20 ÷ 100 =9
2 x 2 x 5 = 20 3 x 3 x 5 = 45 The GCF is 5.
45 x 0.2 = 9
20% off $45 20% equates to 20/100 so 20% of 45 = 45 x 20/100 = 9. 20% of $45 = 9 Therefore 20% off $45 = 45 - 9 = $36
45 = 0.2x x = 45 divided by 0.2 x = 225
900