4*3*6 4*3=12 4*6=24 6*3=18 12+18+24=54 54*2=108 sq ft
None! Very funny!
420 cubic ft.
Length*Width = Area so Width = Area/Length = 40.64 sq ft/12.7 ft = 3.2 ft.
area = width x length width = area/length width = 925 sq ft/37 ft width = 25 ft
135 sq ft
658ft
the perimeter of a rectangular rug is 40 ft. the length is 2 ft longer than the width. find the dimensions
75.58 ft (approx. 75' 7") Pythagoras John
232 ft
Let length be denoted by l, and width by w. Length is 4 ft more than twice the width => l = 2w + 4 five times the width is the same as twice the length increased by 10 feet. =>5w = 2l + 10 Solving the two equations we get l = 40 w = 18 So, the rectangle is 40 ft long and 18 ft wide.
The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.
4*3*6 4*3=12 4*6=24 6*3=18 12+18+24=54 54*2=108 sq ft
None! Very funny!
18,000 ft
420 cubic ft.
Length*Width = Area so Width = Area/Length = 40.64 sq ft/12.7 ft = 3.2 ft.