4*3*6 4*3=12 4*6=24 6*3=18 12+18+24=54 54*2=108 sq ft
None! Very funny!
420 cubic ft.
Length*Width = Area so Width = Area/Length = 40.64 sq ft/12.7 ft = 3.2 ft.
area = width x length width = area/length width = 925 sq ft/37 ft width = 25 ft
135 sq ft
658ft
the perimeter of a rectangular rug is 40 ft. the length is 2 ft longer than the width. find the dimensions
75.58 ft (approx. 75' 7") Pythagoras John
232 ft
The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.
Let length be denoted by l, and width by w. Length is 4 ft more than twice the width => l = 2w + 4 five times the width is the same as twice the length increased by 10 feet. =>5w = 2l + 10 Solving the two equations we get l = 40 w = 18 So, the rectangle is 40 ft long and 18 ft wide.
4*3*6 4*3=12 4*6=24 6*3=18 12+18+24=54 54*2=108 sq ft
None! Very funny!
18,000 ft
420 cubic ft.
Length*Width = Area so Width = Area/Length = 40.64 sq ft/12.7 ft = 3.2 ft.