75.58 ft (approx. 75' 7")
Pythagoras
John
if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
A rectangular prism with a width of 4 inches a height of 6 inches and a depth of 8 inches has a volume of 192 cubic inches.
They are in a ratio 1 to 3 and so the width of the red tile is 20.25 inches
7 inches diagonal top to bottom
Area of a rectangle is width times lenght. 14m in lenght (times) 5m in width = 70m2
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.
The length is 20 cm.
The diagonal length is about 18.44 inches.
the width of the rectangle is 12.....because area= lenght x width so if the lenght is 5 inches and the area is 60....u divide 60 divided by 5 = 12
3.606 inches (rounded)
4 feet high by 8 feet wide = diagonal of 107.28 inches.
The area of a rectangle is length times width. If you have the length and a diagonal, you will first have to figure out the width, using the formula of Pythagoras. length2 + width2 = diagonal2; solving for width: width = square root of (diagonal2 - length2). Once you have the width, just multiply lenght x width.
28 in
77 in
If you mean a length of 16 inches then the width is: 400/16 = 25 feet
if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
Using Pythagoras' theorem the diagonal works out as 51 inches