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Yes! So in conclusion, 1Q, 2C, and 1M are all equivalent. Goodbya, Koda! :P
12-2c = 2c add 2c to both sides 12 = 4c divide both sides by 4 3 = c
An equation where c = 5
Without any information about a or b or c, all that can be said is: a + b + 2c = a + b + 2c Not particularly illuminating!
2c + 3 = 15 Subtract 3 from both sides: 2c = 12 Divide both sides by 2: c = 6