Without any information about a or b or c, all that can be said is:
a + b + 2c = a + b + 2c
Not particularly illuminating!
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(a-d)/2c=b
4ac + 2ad + 2bc +bd = 2a*(2c + d) + b*(2c + d) = (2c + d)*(2a + b)
Not sure about the original formula, but one that works is b = a/(2c + 1)
2b + 2c or 2(b + c)
(a + b)(b - 2c)