answersLogoWhite

0

How much is x3 times x2?

Updated: 12/17/2022
User Avatar

Wiki User

6y ago

Want this question answered?

Be notified when an answer is posted

Add your answer:

Earn +20 pts
Q: How much is x3 times x2?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What is x2 times x3?

If x2 and x3 are meant to represent x2 and x3, then x2 times x3 = x5 You find the product of exponent variables by adding the exponents.


What times x2-x3?

-1


How much to register a ATV in Canada?

It would be about x2 to x3 times as much if you purchased or ordered it from the U.S.


What is x3-x2-x minus 2 factored?

x3-x2


How do you factor x3?

X3 X(X2) X2(X) and, X * X * X


Factor by grouping 3-3x plus x2-x3?

3 - 3x + x2 - x3 = (1 - x)(x2 + 3)


How do you factor x3 plus x2-3x-3?

x3 + x2 - 3x - 3 x(x2 + x - 3) - 3


What is x3-x2 plus 2x factored?

x3 - x2 + 2x = x*(x2 - x + 2) which cannot be factored further.


What is a grouping factor for polynomial x3 ax 3a 3x2?

x3 + ax + 3a + 3x2 = x (x2 + a) + 3 (a + x2) = x (x2 + a) + 3 (x2 + a) = (x2 + a)(x + 3) Checking the work: x3 + ax + 3x2 + 3a or x3 + 3x2 + 3a + ax = x2 (x + 3) + a (3 + x) = x2 (x + 3) + a (x + 3) = (x + 3)(x2 + a)


What is x3 - x2 plus x - 2 factored?

x3 - x2 + x - 2 has no rational factors.


How do you factor x3-x2?

Answer: x (x2-x)


How many times in a twelve hour period does the sum of the digits on a digital clock equal six and prove it?

notation: natural numbers = 0,1, 2, 3, 4, 5, ....., (some define it without the zero, though) <= means smaller than or equal to, {} is set notation and means a set of numbers : (such that) then some condition. For example {x: x is not a duck} is the set of all things not a duck. Our goal is to prove that there are 21 different times. let x1 = hours, x2 = tens of minutes, x3 = minutes. We are going to prove the statement about the set {x1, x2,x3: 1<=x1 <= 12, 0<= x2<=5, 0<=x3 <= 59, x1 + x2 + x3 = 6}. It will be taken by assumption that this set is the set of digital clock combinations that add up to 6. So then, we must prove that there are unique 21 elements in the set {x1 + x2 + x3 : 1<= x1 <= 12, 0<= x2<=5, 0<=x3 <= 59, x1 + x2 + x3 = 6}. {x1 , x2 , x3 : 1<= x1 <= 12, 0<= x2<=5, 0<=x3 <= 59, x1 + x2 + x3 = 6} = {x1 , x2 , x3 : 1<= x1 <= 6, 0<= x2<=5, 0<=x3 <= 5, x1 + x2 + x3 = 6} because x3<=6, and because if x1 >=1, then x2 + x3 <=5, and x3, x2 >= 0 , so surely x3, x2 <= x5. Either x1 = 1, 2, 3, 4, 5, or 6. Next, x1 + x2 + x3 = 6, so x2 + x3 = 6 - x1. There are n+1 natural numbers between 0 and n (I'm being lazy and not proving this, but the proof would be so much longer if I proved it), and since 0 <= x2 <= 5 <= 6-x1, there are at most 6-x1+1 values of x2 for each value of x1. When x1 = 1, there are a maximum of 6, when x1 = 2, there are 6-2+1 = 5, when x1 = 3, there are 6-3+1 = 4, when x1 = 3, there are 3, then 2, and then 1. Summing this up gives us a maximum of 21. So it is at most 21 and at least 21, so exactly 21.