(a - 2)(b + 3)
x^3 + ax + 3a + 3x^2 = (x^3 + 3x^2) + (ax + 3a) = x^2(x + 3) + a(x + 3) = (x + 3)(x^2 + a)
The GCF is 3a
15
2a(3a - 4b + 1)
(a - 2)(b + 3)
It is: 3a(1-4b)
The factors of 3a are 3 and a.
The greatest common factor (GCF) of 2a and 3a is a.
(3a + b)(3a - b)
You would factor 3a + 9b as: 3(a+3b)
3a(2a + 1)
3a - 5 cannot be factored further.
-3(a^2 - 3a + 7)
Since 3a is a factor of 6ab, it is automatically the GCF.
If that's 9a2, the answer is a(a2 - 9a + 3) x(5x2 + 3x - 1) -8d(d2 + 3d + 1)
Do you mean (3ax-15a)+(x-5)?If so, then this is simply a matter of factoring by grouping, which you should have learned in pre-algebra.You should show these steps in your work:1. (3ax-15a)+(x-5)- beginning equation2. 3a(x-5)+1(x-5)- factoring it out3. (3a+1)(x-5)- rule of factoring by groupingYou should learn this method, because it is very simple and helps you a lot in factoring chapters.