To determine how much more than 9p two 2s and one 5 are, first calculate the total value of the two 2s and one 5. This equals (2 \times 2 + 5 = 4 + 5 = 9). Now, subtract 9p from 9 to find the difference: (9 - 9p = 9(1 - p)). Therefore, the result depends on the value of p; if p is less than 1, it is positive, and if p is more than 1, it is negative.
no five fourths is one and one fourth but 5 twos is 2 and a half
5 twos = 10 5/2 = 2.5
3 ones
true
23 + 2 19 + 3 + 3 17 + 5 + 3 17 and 4 twos 17, 2 threes and 2 twos 13 + 7 + 5 13 and 6 twos 13 and 4 threes 11 and 2 sevens 11 and 7 twos and a bunch more up to 10 twos and 5 11 twos and 3
2
11 - 9p.
no five fourths is one and one fourth but 5 twos is 2 and a half
Five twos = 10 is bigger.
5 twos = 10 5/2 = 2.5
Oh, dude, let me break it down for you. So, if we have 3 twos and 5s, that's like 6 plus 15, which is 21. And if we're talking about more than 9P, that's like anything greater than 9. So, technically, 21 is definitely more than 9P.
We can't.
Five twos.
1 five 2 fours 3 threes 4 twos 5 ones
(2+2)x2+(2/2)
(55/5)+55=66
3 ones