To determine how much more than 9p two 2s and one 5 are, first calculate the total value of the two 2s and one 5. This equals (2 \times 2 + 5 = 4 + 5 = 9). Now, subtract 9p from 9 to find the difference: (9 - 9p = 9(1 - p)). Therefore, the result depends on the value of p; if p is less than 1, it is positive, and if p is more than 1, it is negative.
no five fourths is one and one fourth but 5 twos is 2 and a half
5 twos = 10 5/2 = 2.5
3 ones
true
23 + 2 19 + 3 + 3 17 + 5 + 3 17 and 4 twos 17, 2 threes and 2 twos 13 + 7 + 5 13 and 6 twos 13 and 4 threes 11 and 2 sevens 11 and 7 twos and a bunch more up to 10 twos and 5 11 twos and 3
2
11 - 9p.
no five fourths is one and one fourth but 5 twos is 2 and a half
Five twos = 10 is bigger.
5 twos = 10 5/2 = 2.5
We can't.
Oh, dude, let me break it down for you. So, if we have 3 twos and 5s, that's like 6 plus 15, which is 21. And if we're talking about more than 9P, that's like anything greater than 9. So, technically, 21 is definitely more than 9P.
Five twos.
1 five 2 fours 3 threes 4 twos 5 ones
(2+2)x2+(2/2)
3 ones
(55/5)+55=66