Q: How much power is needed to do 1200 Joules of work in 90 seconds?

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1200 seconds

There are 1200/60 = 20 minutes

Calculate the amount of potential energy required. Then divide by the power.

1200/60 = 20 minutes

Fifty.

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The work required to move the truck is 600 N (600 kg-m/sec2) times 30 meters = 18000 joules. If this is done in 15 seconds, the average power was 1200 watts (kg-m2/sec3).

1 Watt = 1 Joule/Sec or Joule = Watt * Time (seconds) So saying that the 1200-W toaster oven is working at full capacity then it is using 1200W * (60 sec * 25) = 1,800,000 joules.

1200 seconds equals 20 minutes. 1200 seconds

There are 60 seconds in one minute. Therefore, 1200 seconds is equal to 1200/60 = 20 minutes.

1200 seconds

1200 seconds

20 minutes. you divide 1200 into 60, because there is 60 seconds in a min.

1200 seconds.Set up a proportion ... 60 sec = x1 min 20 min Cross multiply .1200 = xThere are 1200 seconds in 20 mins.1200

It can last anywhere from 120 - 1200 seconds.

Yes, a 1200 watt amp can power a 300 watt box. The wattage of the amp refers to its maximum power output, so it can deliver up to 1200 watts if needed. As long as the amp is set up properly and not pushed to its maximum capacity, it can safely power a 300 watt box.

There are 1200/60 = 20 minutes

1200sec=20mins=0.4hrs