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First mulitiply Newton x meter to get the energy (or work) required. Then divide the result by the time to get the power.
Power is energy per unit time. So, the required power is 900/90 = 10 Watts.
Work (energy transferred) = force x distance = 200 N x 10 m = 2000 Joule. Power = work / time = 2000 Joules / 8 seconds = 250 Watts.
Power is measured in watts, or joules per second. So in 90 seconds, 1200 joules of work is equal to 1200/90 watts or 13.3 watts.
1 degree = 60 seconds. You now have all the information required to work out the answer to your question.
The power required to do 40 J of work in 5 seconds is 8 watts. This can be calculated by dividing the work (40 J) by the time (5 seconds). The formula for power is Power = Work / Time.
The power required to do 60 joules of work in 20 seconds is determined by the formula: Power = Work / Time. Therefore, Power = 60 joules / 20 seconds = 3 watts. So, 3 watts of power is necessary to do 60 joules of work in 20 seconds.
The power required to do 50 joules of work in 5 seconds is 10 watts. This is calculated by dividing the work done (50 joules) by the time taken (5 seconds), which equals 10 watts.
The power needed to do 50 joules of work in 5 seconds is calculated by dividing the work by the time, which equals to 10 watts. So, 10 watts of power is required to do this amount of work in the given time frame.
First mulitiply Newton x meter to get the energy (or work) required. Then divide the result by the time to get the power.
The power required to do 104 Joules of work in 60 seconds is 1.73 Watts. This is calculated by dividing the work (104 J) by the time taken (60 seconds).
Power is energy per unit time. So, the required power is 900/90 = 10 Watts.
The power required to do 20 joules of work in 2 seconds is 10 watts. This is calculated by dividing the work done (20 joules) by the time taken (2 seconds). Therefore, the power = Work / Time = 20 J / 2 s = 10 W.
300 W
Power is calculated by dividing the work done in Joules by the time taken in seconds. So, if x Joules of work are done in 10 seconds, the power used would be x/10 watts.
The work done in lifting the crate is equal to its change in potential energy: ( \text{Work} = \text{Force} \times \text{distance} = m \cdot g \cdot h ). The power required is the work done divided by the time taken: ( \text{Power} = \frac{\text{Work}}{\text{time}} ). Plug in the values to calculate the power required.
Power is the rate at which work is done. To find the power required to do 100 J of work in 5 s, divide the work by the time: 100 J / 5 s = 20 watts. If the same work is done in 1 s, the power required would be 100 watts, as power is inversely proportional to time.