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How much pure acid should be mixed with 5 gallons of a 20 percent acid solution to get a 50 percent acid solution?
x = amount of acid to add.
y = final volume.
5 gal + x = y
original amount of acid + acid added = final amount of acid
(5 X .2) + x = O.5y
Subtract the second equation from the first one.
5 - 1 + x - x = y - 0.5y
4 = 0.5y
8 = y
Therefore the final volume is 8 gallons.
5 gal + x = 8
x = 3 gal. the amount of pure acid to add.
Check the answer
5 X .2 = 1 gal of acid in original solution.
3 gallons added = 4 gallons total acid in solution.
4 gallons total acid in final solution of 8 gallons total solution = 50% acid.
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How many gallons of a 80 percent acid solution must be mixed with 60 gallons of a 16 percent solution to obtain a solution that is 60 percent?
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