To cover 7,500 square feet to a depth of 4 inches, you first convert the depth to feet, which is 4 inches ÷ 12 inches/foot = 0.33 feet. Then, multiply the area by the depth: 7,500 sq ft × 0.33 ft = 2,475 cubic feet of sand. If you need the amount in cubic yards, divide by 27 (since there are 27 cubic feet in a cubic yard), resulting in approximately 91.67 cubic yards of sand.
Half a cubic foot.
5760 cubic feet of stone.
11,923,200 sq in. of sand.
That depends how deep you want your covering. You'll need a volume of 256 x depth_in_feet cubic feet of dirt to cover the area of 8 ft by 32 ft.
The answer depends on the units that should have been given for the 2 deep: 2 inches, 2 feet, 2 miles - who knows?
Half a cubic foot.
5760 cubic feet of stone.
To give you an answer, we need to know how wide, how long and how deep. You gave us 2 of the 3 numbers we need. No answer for you.
11,923,200 sq in. of sand.
To cover 6 acres with two feet of soil requires 3227 cubic yards of soil. This would require about 1100 3 yard dump truck trips.
You would need about 13 cu yards or about 15 tons.
You will need 1500 cubic feet.
You would need about 1 cubic yard of topsoil to cover a 200 square foot area with 1 inch of soil.
That depends on how deep you want the top soil! 5' X 8' = 40 square feet. If you want it 1' deep you would need 40 Cubic Feet, 3" deep you would need 10 cubic feet of top soil.
25 cubic feet or about 1 cubic yard.
Approximately 24.7 cubic yards or 31.7 tons of gravel.
That depends how deep you want your covering. You'll need a volume of 256 x depth_in_feet cubic feet of dirt to cover the area of 8 ft by 32 ft.