To cover 7,500 square feet to a depth of 4 inches, you first convert the depth to feet, which is 4 inches ÷ 12 inches/foot = 0.33 feet. Then, multiply the area by the depth: 7,500 sq ft × 0.33 ft = 2,475 cubic feet of sand. If you need the amount in cubic yards, divide by 27 (since there are 27 cubic feet in a cubic yard), resulting in approximately 91.67 cubic yards of sand.
Half a cubic foot.
5760 cubic feet of stone.
11,923,200 sq in. of sand.
That depends how deep you want your covering. You'll need a volume of 256 x depth_in_feet cubic feet of dirt to cover the area of 8 ft by 32 ft.
The answer depends on the units that should have been given for the 2 deep: 2 inches, 2 feet, 2 miles - who knows?
Half a cubic foot.
5760 cubic feet of stone.
To give you an answer, we need to know how wide, how long and how deep. You gave us 2 of the 3 numbers we need. No answer for you.
11,923,200 sq in. of sand.
To cover 6 acres with two feet of soil requires 3227 cubic yards of soil. This would require about 1100 3 yard dump truck trips.
You would need about 13 cu yards or about 15 tons.
You will need 1500 cubic feet.
You would need about 1 cubic yard of topsoil to cover a 200 square foot area with 1 inch of soil.
That depends on how deep you want the top soil! 5' X 8' = 40 square feet. If you want it 1' deep you would need 40 Cubic Feet, 3" deep you would need 10 cubic feet of top soil.
Approximately 24.7 cubic yards or 31.7 tons of gravel.
25 cubic feet or about 1 cubic yard.
That depends how deep you want your covering. You'll need a volume of 256 x depth_in_feet cubic feet of dirt to cover the area of 8 ft by 32 ft.