To calculate the amount of water in an 18-foot round pool, you first need to determine the volume. The formula for the volume of a cylinder (pool) is V = πr²h, where r is the radius and h is the height (or depth) of the pool. The radius is half of the diameter, so for an 18-foot pool, the radius is 9 feet. If you assume a typical depth of 4 feet, the volume would be approximately 1,018 cubic feet. Since there are about 7.48 gallons in a cubic foot, this translates to roughly 7,617 gallons of water.
48*18=864
About 7,645 gallons.
The pool volume is 3.14 x 18 x 18 X 4/4 = 1017 cu ft - that's how much water you will need. 1017 cu ft = 7600 gallons
To calculate the volume of water in an 18 ft by 4 ft swimming pool, you also need the depth of the pool. Assuming the pool is uniformly 4 feet deep, the volume can be calculated using the formula for the volume of a rectangular prism: length × width × height. Thus, the volume would be 18 ft × 4 ft × 4 ft = 288 cubic feet. Since there are about 7.48 gallons in a cubic foot, the pool would hold approximately 2,155 gallons of water.
359 gallons for every inch the water is deep.
4ft. by 18 ft.
18 ft x 30 ft x 52 ft = 28080
48*18=864
About 5,730 gallons.
About 7,645 gallons.
The pool volume is 3.14 x 18 x 18 X 4/4 = 1017 cu ft - that's how much water you will need. 1017 cu ft = 7600 gallons
359 gallons for every inch the water is deep.
36 square yards.
18 cu. ft
1.5 feet
18-ft x 9-ft x 4.5-ft = 729 cubic feet = 5,453.3 gallonsThat's the volume of the space with those dimensions.We have no way to know how much water may be in it.It may even be empty.
18 ft * 18 ft * 2 inches = 6 yards * 6 yards * 2/36 yards = 2 cubic yards.