Wiki User
∙ 13y ago-- The force required to lift the crate is equal to its weight.
-- Weight of the crate = (M x g) = 100 x 9.8 = 980 newtons.
-- Work = (force x distance) = 980 x 3 = 2,940 newton-meters = 2,940 joules.
That's the work done to lift the crate, whether the worker takes a millisecond or
a month to do the job. The amount of work the job requires doesn't depend on
how fast it's done.
The rate at which the work is done is called power.
-- If the work is done in 2 seconds, the power is 2,940/2 = 1,470 joules/second = 1,470 watts.
-- If you're being paid by the hour, decide to stretch it out, and take exactly one hour
to do it, then the power is 2,940/3,600 = 0.817 watt.
-- If you're trying to make a good impression on the boss, and you complete the hoist in
1 millisecond, then your power level is 2,940/0.001 = 2,940 kilowatts = 2.94 megawatts.
-- If you could have completed the job a tiny bit faster ... in 1.97 rather than 2.0 seconds ...
then the power would have been 2,940/1.97 = 1,492 watts = exactly 2 horsepower.
But the amount of work is the same in every case.
Wiki User
∙ 13y agow=2.9kilojoules..
80 J
20 crates with 20 eggs leftover
82kg
i done know
w=2.9kilojoules..
twice as much work
The work done on the crate would be 40 joules (work = force x distance).
100KG
Uhh.. about 3fiddy
The work done on the crate is calculated using the equation Work = Force x Distance. Given the time (4 s) and distance (2 m), we would need additional information such as the force applied to the crate to determine the total work done.
100kg
5,2356 dm3
100kg
80 J
50kg?
The work done by a crane lifting a 240 kg crate to a height of 165 meters is equal to the change in potential energy of the crate. The work done can be calculated using the formula: Work = force x distance. In this case, the force is equal to the weight of the crate (240 kg x 9.8 m/s^2) and the distance is 165 meters.