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How much work is done on a 100 kg crate that is hoisted 3 m in a time of 2 s?
Wiki User
∙ 13y ago
w=2.9kilojoules..
Wiki User
∙ 13y ago
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How much work is done on a 100-kg crate that is hoisted 3 m in a time of 2 s?
-- The force required to lift the crate is equal to its weight.-- Weight of the crate = (M x g) = 100 x 9.8 = 980 newtons.-- Work = (force x distance) = 980 x 3 = 2,940 newton-meters = 2,940 joules.That's the work done to lift the crate, whether the worker takes a millisecond ora month to do the job. The amount of work the job requires doesn't depend onhow fast it's done.The rate at which the work is done is called power.-- If the work is done in 2 seconds, the power is 2,940/2 = 1,470 joules/second = 1,470 watts.-- If you're being paid by the hour, decide to stretch it out, and take exactly one hourto do it, then the power is 2,940/3,600 = 0.817 watt.-- If you're trying to make a good impression on the boss, and you complete the hoist in1 millisecond, then your power level is 2,940/0.001 = 2,940 kilowatts = 2.94 megawatts.-- If you could have completed the job a tiny bit faster ... in 1.97 rather than 2.0 seconds ...then the power would have been 2,940/1.97 = 1,492 watts = exactly 2 horsepower.But the amount of work is the same in every case.
How much power is used when 600j of work are done in 10seconds?
Use the definition of power as energy / time. Or work / time; it's basically the same thing.
How much time to push 100 kg for 100 meters?
The answer will depend on the power. The work can be done in one second or a billion years!
What is work done per unit of time?
power
How do you solve for power if mass distance and time is given?
power=work done/time interval
How much work is done on a 100 kg crate that is 2 m in a time of 4 s?
The work done on the crate is calculated using the equation Work = Force x Distance. Given the time (4 s) and distance (2 m), we would need additional information such as the force applied to the crate to determine the total work done.
A crate is pulled across a horizontal floor by a rope At the same time the crate pulls back on the rope in accord with Newton's 3rd law Does the work done on the crate by the rope then equal zero?
No, the work done on the crate by the rope is not zero. The work done is equal to the force exerted by the rope multiplied by the distance the crate is pulled. The fact that the crate pulls back on the rope in accordance with Newton's Third Law does not cancel out the work done by the rope.
If it took 5 seconds to lift the crate using a machine what was the power rating of the machine?
To calculate the power rating of the machine, we need to know the work done in lifting the crate and the time taken. The formula for power is Power = Work / Time. If we know the work done in lifting the crate (measured in joules), we can calculate the power rating.
How much power is required to raise a 30 kg crate a vertical distance of 6 m in a time of 4 seconds?
The work done in lifting the crate is equal to its change in potential energy: ( \text{Work} = \text{Force} \times \text{distance} = m \cdot g \cdot h ). The power required is the work done divided by the time taken: ( \text{Power} = \frac{\text{Work}}{\text{time}} ). Plug in the values to calculate the power required.
A 50kg crate is lifted to a height of 10 meters if it took 5 seconds to lift the crate using a machine what was the power rating of the machine?
The work done to lift the crate is equal to the gravitational potential energy gained: Work = force x distance = weight x height. Here, Work = 50kg x 9.8m/s^2 x 10m = 4900 Joules. Power is work done per unit time, so Power = Work / time = 4900J / 5s = 980 Watts. Therefore, the power rating of the machine is 980 Watts.
How much work is done on a 100-kg crate that is hoisted 3 m in a time of 2 s?
-- The force required to lift the crate is equal to its weight.-- Weight of the crate = (M x g) = 100 x 9.8 = 980 newtons.-- Work = (force x distance) = 980 x 3 = 2,940 newton-meters = 2,940 joules.That's the work done to lift the crate, whether the worker takes a millisecond ora month to do the job. The amount of work the job requires doesn't depend onhow fast it's done.The rate at which the work is done is called power.-- If the work is done in 2 seconds, the power is 2,940/2 = 1,470 joules/second = 1,470 watts.-- If you're being paid by the hour, decide to stretch it out, and take exactly one hourto do it, then the power is 2,940/3,600 = 0.817 watt.-- If you're trying to make a good impression on the boss, and you complete the hoist in1 millisecond, then your power level is 2,940/0.001 = 2,940 kilowatts = 2.94 megawatts.-- If you could have completed the job a tiny bit faster ... in 1.97 rather than 2.0 seconds ...then the power would have been 2,940/1.97 = 1,492 watts = exactly 2 horsepower.But the amount of work is the same in every case.
If a crate trained dog has recently taken to destruction when crated during the day and also damaged the carpet below the crate What could be the cause?
Try not keeping the dog in a crate! They get bored, that's probably why it has resorted to destruction. : : : I am home with my dog all day....winter time, so going out alot less, therefore he is crated alot less...now that I have been going out, this is the behavior I am getting. He is 5 months old, good dog. Not sure if this is teenage issue, separation issue, or maybe I just need to re-crate train or get a bigger crate. He loved his crate early on - hanging out in it all the time. Not so much lately
How much power is required to raise a 200-kg crate a vertical distance of 2 m in a time of 4 s?
The work done to raise the crate is given by the formula W = mgh, where m is the mass of the crate, g is the acceleration due to gravity, and h is the height raised. In this case, W = (200 kg)(9.81 m/s^2)(2 m) = 3924 J. The power required is P = W/t, so P = 3924 J / 4 s = 981 W.
How much space does a large dog need in a cage?
The purpose of a dog crate is to keep the pet contained for any variety of reasons. If the dog has too much room, it may show a tendency to relieve itself inside the crate. However if it has too little room then it will have a hard time laying down or moving around. Good common sense should be used when sizing a dog crate for your pet.
When Pakistan flag was hoisted for the first time and was that before 14th August?
The Pakistan flag was hoisted officially on 14th August, 1947. The Flag was finally approved by the Constituent Assembly on 11th Aug (3 days earlier before hoisting)
Why are London hosting the World Cup?
Since it has been a long time since they hoisted a world cup. They did it in 1966.
If a crate weighing 508 N is resting on a plane inclined 26degrees above the horizontal if acceleration is 4.29 then how fast will the crate be moving after 6 seconds?
To determine the speed of the crate after 6 seconds, we first need to calculate the net force acting on the crate on the inclined plane. This can be done by resolving the weight of the crate into components parallel and perpendicular to the plane. Then, using Newton's second law, F = ma, where F is the net force, m is the mass of the crate, and a is the acceleration, we can find the acceleration down the incline. After finding this acceleration, we can use the kinematic equation v = u + at to calculate the final speed of the crate after 6 seconds, where v is the final velocity, u is the initial velocity (assumed to be 0), a is the acceleration, and t is the time.
