(b x h)/2
Divide the area by height then you get the base.
area of a triangle = 1/2 base x height ie times the area by two then divide by the base = height
The height has not been given but the area of the triangle is: 0.5*height*base
Of a square? (area/height=base) Of a triangle? ({area/height}/2=base) Or of some other shape?
If the shape in question is a triangle, then Area = 0.5 * Base * Height So Height = 2 * Area / Base
The relation between the height of a triangle, its base and its area is given by: Area = 0.5 * Base * Height Therefore, we have: Height = (2 * Area)/ Base.
Divide the area by height then you get the base.
area of a triangle = 1/2 base x height ie times the area by two then divide by the base = height
Area = 1/2*Base*Height so Base = 2*Area/Height
The height has not been given but the area of the triangle is: 0.5*height*base
Of a square? (area/height=base) Of a triangle? ({area/height}/2=base) Or of some other shape?
If the shape in question is a triangle, then Area = 0.5 * Base * Height So Height = 2 * Area / Base
That will depend on the height of the triangle which has not been given. Base = (84*2)/height
Multiply the area by 2 and then divide the result by its height which will give you the base.
area of a triangle is given by the formula 1/2 * base *height therefore the area of the following is 1440 unit square
A triangle and a parallelogram can have the same area if the base and height of the triangle are proportional to the base and height of the parallelogram. Specifically, the area of a triangle is given by ( \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} ), while the area of a parallelogram is ( \text{Area} = \text{base} \times \text{height} ). Therefore, if the base of the parallelogram is twice the base of the triangle and they share the same height, their areas will be equal.
Area of a triangle = base * height / 2 Therefore the base = Area * 2 / height