How to solve for the Quadractic formula 5x2-3x-7 equals 0?

Answer 1

5x2 - 3x - 7 = 0 where a = 5, b = -3, and c = -7

x = [-b ± √b2 - 4(a)(c)]/2a

x = [-(-3) ± √(-3)2 - 4(5)(-7)]/2(5)

x = [3 ± √(9 + 140)]/10

x = (3 ± √149)/10

x = (3 ± 12.21)/10

x = (3 + 12.21)/10 = 15.21/10 = 1.521 or

x = (3 - 12.21)/10 = -9.21/10 = -0.921

The EXACT answer would be x = 3/10 ± √149 /10

Note: 149 is not divisable by a perfect square