0
8 x 0 = 4n
0 = 4n
0/4 = n
0 = n
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How can you solve this problem 100t-16t exponent 2 equals 0?
100t -16t2 = 0 t4(25-4t) = 0 t = 0 or t = 25/4
Solve 2x²-2x plus 1 equals 0?
Unfortunately you cannot solve this problem since the domain of x (b2-4ac) = 4-4*2*1 = -4Since the root of a negative number does not exist, this problem is nog solvable without the use of imaginary numbers.
How do you solve x³-4x equals 0 algebraically?
Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.
Solve the quadratic equation using factoring 9x2 - 16 equals 0?
(3x+4)(3x-4)=0 x=±4/3
How do you solve for x in the problem x - 4 equals 3x?
Subtract x so -4 = 2x/ x= -2
How to solve that problem absolute value of 7 - y - 4 equals 0?
y = 3, 6
How can you solve this problem 100t-16t exponent 2 equals 0?
100t -16t2 = 0 t4(25-4t) = 0 t = 0 or t = 25/4
How do you solve the problem 5-2y equals 2?
y=4
How do you solve this problem 9v2-4 equals 0?
9v2 - 4 = 0 Add 4 to both sides 9v2 = 4 Take square roots of both sides: ±3v = ±2 so that v = ±2/3
Solve 2x²-2x plus 1 equals 0?
Unfortunately you cannot solve this problem since the domain of x (b2-4ac) = 4-4*2*1 = -4Since the root of a negative number does not exist, this problem is nog solvable without the use of imaginary numbers.
How do you solve x³-4x equals 0 algebraically?
Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.
Solve the quadratic equation using factoring 9x2 - 16 equals 0?
(3x+4)(3x-4)=0 x=±4/3
How do you solve -4x-2 equals -2?
-4x-2+2=-2+2. -4x/-4=0/-4 x=0
How do you solve for x in the problem x - 4 equals 3x?
Subtract x so -4 = 2x/ x= -2
How do you solve xsquared plus 1over4x equals 0?
x2+1/4x = 0 x(x+1/4) = 0 Therefore: x = 0 or x = -1/4
Solve this equation x2 - 8x plus 17 equals 0?
(4 ± i2) where i2 = -1
Solve the quadratic equation x squares -12x-64 equals 0?
(x - 16)(x + 4) = 0 so x = -4 or 16
