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Solve the quadratic equation using factoring 9x2 - 16 equals 0?
Wiki User
∙ 11y ago
(3x+4)(3x-4)=0
x=±4/3
Wiki User
∙ 11y ago
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What makes a quadratic equation?
When the equation is a polynomial whose highest order (power) is 2. Eg. y= x2 + 2x + 10. Then you can use quadratic formula to solve if factoring is not possible.
What is the solution to 4 equals 2b plus b squared?
To find the solution to this equation, you need to rearrange the terms and solve for the variable. 4 = 2b + b^2 can be rewritten as b^2 + 2b - 4 = 0. You can then solve this quadratic equation by factoring, completing the square, or using the quadratic formula.
Name four ways to solve a quadraic equation?
Four? Factoring Graphing Quadratic Equation Completing the Square There may be more, but there's at least four.
Solve this quadratic equation x2 plus 2x - 22 equals 0?
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
How do you solve 4x2 minus 30x plus 45 by factoring?
The discriminant for the quadratic is b2-4ac = 302 - 4*4*45 = 900 - 720 = 180 Since 180 is not a perfect square, the roots of the equation are irrational and it is far from straightforward to solve such an equation by factoring.
Y equals b plus x plus x2?
y=b+x+x^2 This is a quadratic equation. The graph is a parabola. The quadratic equation formula or factoring can be used to solve this.
What does quadratic equations using the factoring method means?
It means you are required to "solve" a quadratic equation by factorising the quadratic equation into two binomial expressions. Solving means to find the value(s) of the variable for which the expression equals zero.
Which of the following are techniques you have learned so far to solve a quadratic equation?
Solve by factoring. Solve by taking the square root of both sides.
What makes a quadratic equation?
When the equation is a polynomial whose highest order (power) is 2. Eg. y= x2 + 2x + 10. Then you can use quadratic formula to solve if factoring is not possible.
Solve the quadratic equation y2-15 equals 0?
y=±√15
What is the solution to 4 equals 2b plus b squared?
To find the solution to this equation, you need to rearrange the terms and solve for the variable. 4 = 2b + b^2 can be rewritten as b^2 + 2b - 4 = 0. You can then solve this quadratic equation by factoring, completing the square, or using the quadratic formula.
Name four ways to solve a quadraic equation?
Four? Factoring Graphing Quadratic Equation Completing the Square There may be more, but there's at least four.
What equation could you use to solve o equals 4x2-3x-2?
Quadratic equation formula
Solve this quadratic equation x2 plus 2x - 22 equals 0?
Using the quadratic equation formula:- x = 3.795831523 or x = -5.795831523
How do you solve 4x2 minus 30x plus 45 by factoring?
The discriminant for the quadratic is b2-4ac = 302 - 4*4*45 = 900 - 720 = 180 Since 180 is not a perfect square, the roots of the equation are irrational and it is far from straightforward to solve such an equation by factoring.
How do you solve the equation 7r2 equals 70r-175?
7r2 = 70r-175 Rearrange the equation and treat it as a quadratic equation: 7r2-70r+175 = 0 Divide all terms by 7: r2-10+25 = 0 Solve by factoring or using the quadratic equation formula or by completing the square: (r-5)(r-5) x = 5 and x also = 5 (they both have equal roots)
Can you solve a quadratic equation without factoring?
using the quadratic formula or the graphics calculator. Yes, you can do it another way, by using a new method, called Diagonal Sum Method, that can quickly and directly give the 2 roots, without having to factor the equation. This method is fast, convenient and is applicable to any quadratic equation in standard form ax^2 +bx + c = 0, whenever it can be factored. It requires fewer permutations than the factoring method does, especially when the constants a, b, and c are large numbers. If this method fails to get answer, then consequently, the quadratic formula must be used to solve the given equation. It is a trial-and-error method, same as the factoring method, that usually takes fewer than 3 trials to solve any quadratic equation. See book titled:" New methods for solving quadratic equations and inequalities" (Trafford Publishing 2009)
