One solution is 44 - (4 + 4)/4 = 44 - 8/4 = 44 - 2 = 42
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42 * 5/6 = 35
(4/4) + (4/4) = 2 (42 - (4+4)) /4 = 2
35/42 - 12/42 = 23/42
35/42 - 12/42 = 23/42
Call the unknown numbers s and l for smaller and larger respectively. From the problem statement, l - s = 14 and 4s - 3l = 45. Transpose the first equation to result in l = 14 + s and substitute this into the second equation to result in 4s - 3(14 + s) =45, or 4s - 42 - 3s = 45. or s = 45 + 42 = 87. l is then 101.