42 * 5/6 = 35
(4/4) + (4/4) = 2 (42 - (4+4)) /4 = 2
35/42 - 12/42 = 23/42
35/42 - 12/42 = 23/42
Call the unknown numbers s and l for smaller and larger respectively. From the problem statement, l - s = 14 and 4s - 3l = 45. Transpose the first equation to result in l = 14 + s and substitute this into the second equation to result in 4s - 3(14 + s) =45, or 4s - 42 - 3s = 45. or s = 45 + 42 = 87. l is then 101.
Not sure about five, but you can make 42 with 6 2s with this method: 2[(22)! - (2/2) - 2] = 42
Five multiples of 42 are 1, 2, 6, 7, 21, 42.
iPhone 4s is easier to use, but it depends on which Htc, I would say the iPhone 4s
One possible way: Make a 10 using five 4s as follows: 4 + 4 + (4 + 4)/4 = 10 Make another two 10s using five 4s in each. Multiply these three 10s.
no
she use an iphone 4s
There is not enough information in the question to answer the question. It depends on what happens in the ellipsis. If the number of fours keeps increasing forever then it is not a rational number, but if it settles at three 4s, or goes one 4, two 4s, three 4s (and maybe four 4s, five 4s) and then back to one 4 then it is.
7 and 2/4s
4!/4 - 4/4 = 5
(42 ÷ 6) × 5 = 35
42*5/6 = 35
42 * 5/6 = 35