Not sure about five, but you can make 42 with 6 2s with this method:
2[(22)! - (2/2) - 2] = 42
22 + 22 - 2 = 42
You can use three 2s to make 26 as follows (2x2)! + 2 = 26 So you can simply make 26 with five 2s as (2x2!) + 2 - 2 + 2 = 26
(2x2x2)/2 + 2
Two will go into forty two twenty one times.
(22/2+2)x2
22 + 22 - 2 = 42
2x2x2+2/2 = 9
You can use three 2s to make 26 as follows (2x2)! + 2 = 26 So you can simply make 26 with five 2s as (2x2!) + 2 - 2 + 2 = 26
42
To use five 2s to make 3, you can employ a mathematical operation like exponentiation. One way to achieve this is by arranging the 2s as follows: (2^2) - (2/2) = 3. This expression involves raising 2 to the power of 2 (which equals 4) and then subtracting the result of dividing 2 by 2 from it, resulting in 3.
(2x2x2)/2 + 2
Two will go into forty two twenty one times.
(22/2+2)x2
42 can be divided by 2 once. The result, 21, is not divisible by 2.
2s(-s^3 + 2s^2 - 5) -2s(s^3 - 2s^2 + 5)
Five multiples of 42 are 1, 2, 6, 7, 21, 42.
Including 2 and 42 there are 15 which are:- 2 12 20 21 22 23 24 25 26 27 28 29 32 and 42