20x2 - 3x + 10 does not have any real factors.
(5x - 2)(x - 5)
x(x + 9)(x + 1)
x2+2x-120 = (x+12)(x-10) when factored
b= 10
20x2 - 3x + 10 does not have any real factors.
(3r + 2)(r - 5)
(5x - 2)(x - 5)
x(x + 9)(x + 1)
x(x + 9)(x + 1)
x2+2x-120 = (x+12)(x-10) when factored
Factor as : (x+9)(x+10) using the first terms ( x terms) multiply to x2; the last terms multiply to 90; the sum of 9x + 10 x = 19x
The factors are [3x + 5 - 2*sqrt(10)] and [3x 5 + 2*sqrt(10)].
It is 16x squared plus 80x plus 100.Very complicated!
b= 10
109 = 9 + 100
16